IBPS RRB Clerk Prelims Full Test 4

1. Directions: Study the following information carefully and answer the question that follows:

There are eight people, M, N, O, P, Q, R, S, and T, sitting in a circular manner not necessarily in the same order and all are facing away from the center. S is sitting second to the left of O, and to the immediate right of M. T is sitting exactly opposite to R and third to the right of O.N is sitting to the immediate right of P.

Question:

Who is sitting exactly opposite to O?

A. N

B. O

C. P

D. Q

E. T

Solution

Eight people: M, N, O, P, Q, R, S, and T

1) S is sitting second to the left of O, and to the immediate right of M

2) T is sitting exactly opposite to R and third to the right of O

3) N is sitting to the immediate right of P

This is only possible if N is sitting to the immediate left of T

Thus, the final arrangement is:

Hence, Q is sitting exactly opposite to O

2. Directions: Study the following information carefully and answer the question that follows:

2. Which of the following are sitting opposite to each other?

A. M, N

B. P, S

C. Q, P

D. O, M

E. S, N

Solution

Eight people: M, N, O, P, Q, R, S, and T

1) S is sitting second to the left of O, and to the immediate right of M

2) T is sitting exactly opposite to R and third to the right of O

3) N is sitting to the immediate right of P

This is only possible if N is sitting to the immediate left of T

Thus, the final arrangement is:

Hence, S and N are sitting opposite to each other.

3.Directions: Study the following information carefully and answer the question that follows:

Question:

3. How many people are sitting between P and S, counting from the right of P?

A. 1

B. 2

C. 3

D. 4

E. 5

Solution

Eight people: M, N, O, P, Q, R, S, and T

1) S is sitting second to the left of O, and to the immediate right of M

2) T is sitting exactly opposite to R and third to the right of O

3) N is sitting to the immediate right of P

This is only possible if N is sitting to the immediate left of T

Thus, the final arrangement is:

4.Directions: Study the following information carefully and answer the question that follows:

Question:

4. Which of the following statement is incorrect with respect to the position of T?

A. To the immediate right of N

B. To the immediate left of M

C. Second to the right of P

D. Third to the left of S

E. Opposite to R.

Solution

Eight people: M, N, O, P, Q, R, S, and T

1) S is sitting second to the left of O, and to the immediate right of M

2) T is sitting exactly opposite to R and third to the right of O

3) N is sitting to the immediate right of P

This is only possible if N is sitting to the immediate left of T

Thus, the final arrangement is:

∵ T is sitting to the immediate left of Q

Hence, the statement ‘To the immediate left of M’ is incorrect with respect to the position of T

5.Directions: Study the following information carefully and answer the question that follows:

Question:

5. If R and S interchange their positions, then who will be sitting second to the left of R?

A. M

B. N

C. O

D. P

E. Q80% answered correctly

Solution

Eight people: M, N, O, P, Q, R, S, and T

1) S is sitting second to the left of O, and to the immediate right of M

2) T is sitting exactly opposite to R and third to the right of O

3) N is sitting to the immediate right of P

This is only possible if N is sitting to the immediate left of T

Thus, the final arrangement is:

Hence, if R and S interchanges their positions, then Q will be sitting second to the left of R

Direction: Study the following information to answer the given questions.

A man starts walking from point K, he walks 10 m in the east direction and reached at point L, after that he takes right turn and walks 8 m to reach at point M. From the point M, he takes left turn and walks 9 m to reach at point N and again takes left turn and walks 12 m to reach at point O. Finally he takes left turn and walks 19 m to reach at point P.

6. What is the distance between initial point and final point?

A. 8 m

B. 4 m

C. 12 m

D. 10 m

E. 9 m

Solution

We have drawn the figure according to the information given in the question,

From the figure, the distance ON = 12 and LM = 8

It is clear that the distance between initial point and final point = ON – LM = 12 – 8 = 4 m.

Hence, ‘4 m’ is the correct answer.

Direction: Study the following information to answer the given questions.

7. What is the direction of P with respect to K?

A. North

B. East

C. West

D. South

E. None of these

Solution

We have drawn the figure according to the information given in the question,

Thus, the point P is at the North direction with respect to point K.

Hence, ‘North’ is the correct answer.

Direction: Study the following information to answer the given questions.

Question:

8. If a man walks 12 m towards the south from point P and he takes a left turn and walks for another 19 m, which of the following point would he reach?

A. M

B. L

C. N

D. O

E. None of these

Solution

We have drawn the figure according to the information given in the question,

From the above diagram, the person will reach point N.

Hence, ‘N’ is the correct answer.

Direction: Study the following information to answer the given questions.

Question:

9. What is the shortest distance between M and O?

A. 21 m

B. 16 m

C. 17 m

D. 19 m

E. 15 m

Solution

We have drawn the figure according to the information given in the question,

From the above diagram,

Distance between M and N = 9 m

Distance between N and O = 12 m

By Pythagoras’ theorem,

MO² = MN² + NO² = 9² +12²

= 81 + 144 = 225

Hence, the shortest between M and O = 15 m.

10. If it is possible to make only one meaningful English word with the third, the fourth, the seventh, and the eighth letters of the word SAILBOAT, which of the following will be the third letter of that word from left? If no such word can be made give ‘X’ as the answer and if more than one such word can be made give ‘Y’ as the answer.

A. A

B. L

C. I

D. X

E. Y

Solution

Given Word	S A I L B O A T
Chosen Letters	I L A T
Only possible word	T A I L
The third letter of the possible word	I

Hence, the third letter is I.

Direction: Study the following information carefully to answer the given questions.
Nine people – P, Q, R, S, T, V, W, X, and Z, work in a school at different posts. Each person occupies exactly one post among Director, Principal, HOD, Professor, Teacher, Counselor, Coach, Assistant, and Clerk, with the respective level of seniority, i.e. director being the most senior and the clerk being the most junior designation. X is the HOD. V is senior to only two people. Only three people are senior to P. Either R or T is the Teacher. Q is not the most senior person in the school. Neither Q nor W is the Counselor or the Assistant. T is senior to only Z.

Question:

11. Who is the most senior in the school?

A. R

B. S

C. T

D. V

E. W

Solution

Given:

Nine people – P, Q, R, S, T, V, W,X, and Z
Nine designations – Director, Principal, HOD, Professor, Teacher, Counselor, Coach, Assistant, and Clerk
The designations are in the order of seniority, i.e. the director is the most senior and the clerk is the most junior designation.

1. X is the HOD.
2. V is senior to only two people.
3. Only three people are senior to P.

Designation	Person
Director
Principal
HOD	X
Professor	P
Teacher
Counselor
Coach	V
Assistant
Clerk

4. T is senior to only Z.
5. Either R or T is the Teacher.
6. Q is not the most senior person in the school.
7. Neither Q nor W is the Counselor or the Assistant.

Since W is the director.

Hence, W is the most senior in the school.

Question:

12. Who is the Counselor?

A. T

B. P

C. Q

D. R

E. S

Solution

Given:

1. X is the HOD.
2. V is senior to only two people.
3. Only three people are senior to P.

Designation	Person
Director
Principal
HOD	X
Professor	P
Teacher
Counselor
Coach	V
Assistant
Clerk

4. T is senior to only Z.
5. Either R or T is the Teacher.
6. Q is not the most senior person in the school.
7. Neither Q nor W is the Counselor or the Assistant.

Hence, S is the Counselor.

Question:

13. What is the designation of Q?

A. Counselor

B. Director

C. Assistant

D. Principal

E. Clerk

Solution

Given:

1. X is the HOD.
2. V is senior to only two people.
3. Only three people are senior to P.

Designation	Person
Director
Principal
HOD	X
Professor	P
Teacher
Counselor
Coach	V
Assistant
Clerk

4. T is senior to only Z.
5. Either R or T is the Teacher.
6. Q is not the most senior person in the school.
7. Neither Q nor W is the Counselor or the Assistant.

Hence, Q is the Principal.

Question:

14. How many people are junior to R?

A. Five people

B. Four people

C. Three people

D. Two people

E. One person

Solution

Given:

1. X is the HOD.
2. V is senior to only two people.
3. Only three people are senior to P.

Designation	Person
Director
Principal
HOD	X
Professor	P
Teacher
Counselor
Coach	V
Assistant
Clerk

4. T is senior to only Z.
5. Either R or T is the Teacher.
6. Q is not the most senior person in the school.
7. Neither Q nor W is the Counselor or the Assistant.

R is the Teacher.

Hence, four people are junior to R.

Question:

15. Who is the Clerk?

A. Z

B. X

C. Q

D. W

E. T

Solution

Given:

1. X is the HOD.
2. V is senior to only two people.
3. Only three people are senior to P.

Designation	Person
Director
Principal
HOD	X
Professor	P
Teacher
Counselor
Coach	V
Assistant
Clerk

4. T is senior to only Z.
5. Either R or T is the Teacher.
6. Q is not the most senior person in the school.
7. Neither Q nor W is the Counselor or the Assistant.

Hence, Z is the Clerk.

16. Directions: In the following question assuming the given statements to be true, find which of the conclusion among given conclusions is/are definitely true and then give your answers accordingly.

Statements:

S = T = R; T = W = U < G

Conclusions:

I. S < G

II. G > R

A. Only Conclusion I is true.

B. Only Conclusion II is true.

C. Both Conclusions I and II are true.

D. Either Conclusion I or II is true.

E. Neither Conclusion I nor II is true.

Solution

Given statements: S = T = R; T = W = U < G

On combining we get: S = R = T = W = U < G

Conclusions:

I. S < G → True (as S = R = T = W = U < G → therefore S < G)

II. G > R → True (as R = T = W = U < G → therefore R < G → G > R )

Hence, both conclusions I and II are true.

17.Directions: In the following question assuming the given statements to be true, find which of the conclusion among given conclusions is/are definitely true and then give your answers accordingly.

Statements:

F ≤ D; A < B = C; D ≤ E < C

Conclusions:

I. E > F

II. E = F

A. Either Conclusion I or II is true.

B. Both Conclusions I and II are true.

C. Neither Conclusion I nor II is true.

D. Only Conclusion I is true.

E. Only Conclusion II is true.

Solution

Given statements:

F ≤ D; A < B = C; D ≤ E < C

On combining we get: A < B = C > E ≥ D ≥ F

Conclusions:

I. E > F → False (as E ≥ D ≥ F → E ≥ F)

II. E = F → False (as E ≥ D ≥ F → E ≥ F)

Note: Conclusion I and II are complementary pairs.

Hence, either conclusion I or II is true.

18.Directions: In the following question assuming the given statements to be true, find which conclusion among the given conclusions is/are definitely true and then give your answers accordingly.

Statements: Y < O = R > T; A > X = T

Conclusions:

I. X < Y

II. R > A

A. Only Conclusion I is true.

B. Only Conclusion II is true.

C. Both Conclusions I and II are true.

D. Either Conclusion I or II is true.

E. Neither Conclusion I nor II is true.

Solution

Given statements: Y < O = R > T; A > X = T

On combining we get: A > X = T < R = O > Y

Conclusions:

I. X < Y → False (as X = T < R = O > Y → thus a clear relation between X and Y cannot be determined)

II. R > A → False (as A > X = T < R → thus a clear relation between R and A cannot be determined)

Hence, neither conclusion I nor II is true.

Directions: Study the following information carefully to answer the given questions:S N 4 = Q £ α Y R A Δ 7 $ B Z 9 E G β @ C F 1 3 # I L ©

Question:

19. Four of the following five are alike in a certain way based on the positions of the elements in the above arrangement and hence form a group. Which one does not belong to the group?

A. 4NIL

B. £Q13

C. SQ©3

D. £Y1C

E. =#4I

Solution

Given series:

Left Side S N 4 = Q £ α Y R A Δ 7 $ B Z 9 E G β @ C F 1 3 # I L © Right Side

Here In all groups of elements except ‘=#4I’, the third and fourth elements occupies the same positions from the right end in the given arrangement as the first and second elements occupies from the left end respectively.Hence, ‘=#4I’ does not belong to the group.

Directions:Study the following information carefully to answer the given questions: S N 4 = Q £ α Y R A Δ 7 $ B Z 9 E G β @ C F 1 3 # I L ©

Question:

20. How many such numbers are there in the given series, each of which is either immediately followed by a symbol or immediately preceded by a letter, but not both?

A. Two

B. Three

C. Four

D. Five

E. None of these

Solution

Given series:

Left Side S N 4 = Q £ α Y R A Δ 7 $ B Z 9 E G β @ C F 1 3 # I L © Right Side

Numbers which are either immediately followed by a symbol or immediately preceded by a letter, but not both:

S N 4 = Q £ α Y R A Δ 7 $ B Z 9 E G β @ C F 1 3 # I L ©

Hence, there are 4 Numbers that are either immediately followed by a symbol or immediately preceded by a letter, but not both: 7 9 1 3

Hence, four is the correct answer.

Mistake Points

Either precede or followed by means that one of the conditions must be followed. For example: In the question need to find the number which is either followed by a symbol or immediately preceded by a letter but not both.

Directions:Study the following information carefully to answer the given questions: S N 4 = Q £ α Y R A Δ 7 $ B Z 9 E G β @ C F 1 3 # I L ©

Question:

21. If 4 N Q is related to Y R £ in the same way as Z B E is related to?

A. C F β

B. @ C G

C. @ β F

D. @ C E

E. None of these

Solution

Given Series

Left Side S N 4 = Q £ α Y R A Δ 7 $ B Z 9 E G β @ C F 1 3 # I L © Right Side

The pattern followed here is,

4 + 5 = Y;

N + 7 = R;

Q + 1 = £

Similarly,

Z + 5 = @;

B + 7 = C;

E + 1 = GHence, @CG is the correct answer.

Directions:Study the following information carefully to answer the given questions: S N 4 = Q £ α Y R A Δ 7 $ B Z 9 E G β @ C F 1 3 # I L ©

Question:

22. How many such alphabets are there in the given series, each of which are immediately preceded by an alphabet and followed by a number?

A. One

B. Three

C. More than three

D. Two

E. None of these

Solution

Given series:

Left Side S N 4 = Q £ α Y R A Δ 7 $ B Z 9 E G β @ C F 1 3 # I L © Right Side

1) Alphabets which are immediately preceded by an alphabet and followed by a number:

S N 4 = Q £ α Y R A Δ 7 $ B Z 9 E G β @ C F 1 3 # I L ©Hence, there are 3 symbols which are immediately preceded by a number and followed by an alphabet: SN4, BZ9, and CF1.

Directions:Study the following information carefully to answer the given questions: S N 4 = Q £ α Y R A Δ 7 $ B Z 9 E G β @ C F 1 3 # I L ©

Question:

23. If all the numbers in the above arrangement are dropped, then which of the following will be the seventeen from the right end?

A. R

B. α

C. @

D. Y

E. £

Solution

Given series:

Left Side S N 4 = Q £ α Y R A Δ 7 $ B Z 9 E G β @ C F 1 3 # I L © Right Side

1) If all the numbers are dropped:

S N = Q £ α Y R A Δ $ B Z E G β @ C F # I L ©

2) 17^thletter from the right end is YHence, the element which is seventeen from right end is ‘Y’.

Direction: Study the information given below carefully and answer the question that follow.There are seven members in a family, in which two married couples. F is mother of R. B is aunt of P. C is father- in law of Q who is not wife of R. C is brother of B. Q is mother of G. B is sister – in – law of F. B is not married. P and R are brothers. C has only two children.

Question:

24. How G is related to B?

A. Sister

B. Grandfather

C. Father

D. Grandmother

E. Can’t be determined60% answered correctly

Solution

Preparing the family tree using the following symbols:

The gender of G cannot be determined.

So, G is either granddaughter or grandson.

Hence, cannot be determined is the answer.

Direction: Study the information given below carefully and answer the question that follow. There are seven members in a family, in which two married couples. F is mother of R. B is aunt of P. C is father- in law of Q who is not wife of R. C is brother of B. Q is mother of G. B is sister – in – law of F. B is not married. P and R are brothers. C has only two children.

Question:

25. Who among the following is the sister-in-law of R?

A. B

B. P

C. Q

D. G

E. None of these

Solution

Preparing the family tree using the following symbols:

Hence, Q is the sister-in-law of R.

Direction: Study the information given below carefully and answer the question that follow. There are seven members in a family, in which two married couples. F is mother of R. B is aunt of P. C is father- in law of Q who is not wife of R. C is brother of B. Q is mother of G. B is sister – in – law of F. B is not married. P and R are brothers. C has only two children.

Question:

26. Who is the husband of Q?

A. R

B. P

C. B

D. C

E. G

Solution

Preparing the family tree using the following symbols:

Hence, P is the husband of Q.

27. How many pairs of letters are there in the word “JURISDICTION” that have the same number of letters between them in the word (in both forward and backward directions), as they have in the English alphabetical series?

A. One

B. Five

C. Four

D. Two

E. Three

Solution

Given word: JURISDICTION

The given word can be represented as follows:

Thus, there is three pairs → Forward: IN, Backward: NO, CJ

Hence, three is the correct answer.

Direction: Study the following information carefully to answer the given questions:

Eight persons A, B, C, D, E, F, G, and H live on different floors of a building. The bottom-most floor is numbered as 1, the floor above it as 2, and so on. Only two persons live on the floors below G. Only one person lives between G and A. A does not live on the lowermost floor. Only two persons live between H and B. H lives on an odd-numbered floor but not the 7^th floor. Only two persons live between A and E. F lives on a floor below B. C does not live on the 7^th floor.

Question:

28. Who lives on the topmost floor?

A. D

B. H

C. C

D. F

E. E

Solution

Persons: A, B, C, D, E, F, G, and H

1. Only two persons live on the floors below G and only one person lives between G and A. Also, A does not live on the lowermost floor.

2. Only two persons live between H and B. Also.

3. H lives on an odd-numbered floor but not the 7th floor.

According to condition number 2, H can be placed on the 1^st, 7^th, or 8^th floor but according to condition number 3, H must be placed on the 1^st floor.

Floor	Person
8
7
6
5	A
4	B
3	G
2
1	H

4. Only two persons live between A and E.

5. F lives on a floor below B.

Floor	Person
8	E
7
6
5	A
4	B
3	G
2	F
1	H

6. C does not live on the 7th floor.

The only place left for C is the 6^th floor. Accordingly, the only place left for D is the 7^th floor.

Floor	Person
8	E
7	D
6	C
5	A
4	B
3	G
2	F
1	H

Hence, E lives on the topmost floor.

Direction: Study the following information carefully to answer the given questions:

Question:

29. Four of the following five are alike in a certain way based on their arrangement. Find the one which does not belong to that group?

A. G

B. C

C. A

D. D

E. H

Solution

Persons: A, B, C, D, E, F, G, and H

1. Only two persons live on the floors below G and only one person lives between G and A. Also, A does not live on the lowermost floor.

2. Only two persons live between H and B. Also.

3. H lives on an odd-numbered floor but not the 7th floor.

According to condition number 2, H can be placed on the 1st, 7th, or 8th floor but according to condition number 3, H must be placed on the 1st floor.

Floor	Person
8
7
6
5	A
4	B
3	G
2
1	H

4. Only two persons live between A and E.

5. F lives on a floor below B.

Floor	Person
8	E
7
6
5	A
4	B
3	G
2	F
1	H

6. C does not live on the 7th floor.

The only place left for C is the 6th floor. Accordingly, the only place left for D is the 7th floor.

Floor	Person
8	E
7	D
6	C
5	A
4	B
3	G
2	F
1	H

G, A, D, and H, all live on odd-numbered floors, whereas, C lives on an even-numbered floor.

Hence, the correct option is 2.

Direction: Study the following information carefully to answer the given questions:

Question:

30. Who lives four floors above G?

A. D

B. E

C. C

D. A

E. F

Solution

Persons: A, B, C, D, E, F, G, and H

1. Only two persons live on the floors below G and only one person lives between G and A. Also, A does not live on the lowermost floor.

2. Only two persons live between H and B. Also.

3. H lives on an odd-numbered floor but not the 7th floor.

According to condition number 2, H can be placed on the 1st, 7th, or 8th floor but according to condition number 3, H must be placed on the 1st floor.

Floor	Person
8
7
6
5	A
4	B
3	G
2
1	H

4. Only two persons live between A and E.

5. F lives on a floor below B.

Floor	Person
8	E
7
6
5	A
4	B
3	G
2	F
1	H

6. C does not live on the 7th floor.

The only place left for C is the 6th floor. Accordingly, the only place left for D is the 7th floor.

Floor	Person
8	E
7	D
6	C
5	A
4	B
3	G
2	F
1	H

Hence, D lives four floors above G.

Direction: Study the following information carefully to answer the given questions:

Question:

31. Who lives on second floor?

A. A

B. E

C. F

D. G

E. None of these

Solution

Persons: A, B, C, D, E, F, G, and H

1. Only two persons live on the floors below G and only one person lives between G and A. Also, A does not live on the lowermost floor.

2. Only two persons live between H and B. Also.

3. H lives on an odd-numbered floor but not the 7th floor.

According to condition number 2, H can be placed on the 1st, 7th, or 8th floor but according to condition number 3, H must be placed on the 1st floor.

Floor	Person
8
7
6
5	A
4	B
3	G
2
1	H

4. Only two persons live between A and E.

5. F lives on a floor below B.

Floor	Person
8	E
7
6
5	A
4	B
3	G
2	F
1	H

6. C does not live on the 7th floor.

The only place left for C is the 6th floor. Accordingly, the only place left for D is the 7th floor.

Floor	Person
8	E
7	D
6	C
5	A
4	B
3	G
2	F
1	H

Hence, F lives on 2nd floor.

Direction: Study the following information carefully to answer the given questions:

Question:

32. How many persons live above B?

A. 4

B. 5

c. 6

D. 2

E. 1

Solution

Persons: A, B, C, D, E, F, G, and H

1. Only two persons live on the floors below G and only one person lives between G and A. Also, A does not live on the lowermost floor.

2. Only two persons live between H and B. Also.

3. H lives on an odd-numbered floor but not the 7th floor.

According to condition number 2, H can be placed on the 1st, 7th, or 8th floor but according to condition number 3, H must be placed on the 1st floor.

Floor	Person
8
7
6
5	A
4	B
3	G
2
1	H

4. Only two persons live between A and E.

5. F lives on a floor below B.

Floor	Person
8	E
7
6
5	A
4	B
3	G
2	F
1	H

6. C does not live on the 7th floor.

The only place left for C is the 6th floor. Accordingly, the only place left for D is the 7th floor.

Floor	Person
8	E
7	D
6	C
5	A
4	B
3	G
2	F
1	H

Hence, 4 persons live above B.

Directions: Study the following information to answer the given questions.

In a certain code language,

‘She loves dog’ is coded as ‘ rst abc ptr’,

‘She likes travelling’ is coded as ‘bca ptr efg’,

‘Dog likes bone’ is coded as ‘mno rst bca’,

‘Ravi has dog’ is coded as ‘xyz jkl rst’.

Question:

33. What is the code for ‘loves travelling’?

A. abc etg

B. cba etg

C. efg cba

D. cfg abc

E.abc efg

Solution

According to the information given,

Word for the code ‘ptr’: she.

Word for the code ‘rst’: dog.

Word for the code ‘bca’: likes.

From the first line we can say that the code for ‘loves’ is ‘abc’.

From the second line we can say that the code for ‘travelling’ is ‘efg’.

Hence, the code for ‘loves travelling’ is ‘abc efg’.

Directions: Study the following information to answer the given questions.

In a certain code language,

‘She loves dog’ is coded as ‘ rst abc ptr’,

‘She likes travelling’ is coded as ‘bca ptr efg’,

‘Dog likes bone’ is coded as ‘mno rst bca’,

‘Ravi has dog’ is coded as ‘xyz jkl rst’.

Question:

34. What is the code for ‘Ravi loves cat’, if the code for cat is opq?

A. xyz abc opq

B. xyz jkl opq

C. jkl abc opq

D. Either 1 or 3

E. Either 2 or 3

Solution

According to the information given,

Word for the code ‘ptr’: she.

Word for the code ‘rst’: dog.

Word for the code ‘bca’: likes.

Word for the code ‘abc’: loves.

Word for the code ‘efg’: travelling.

Word for the code ‘mno’: bone.

‘Ravi’ is coded as either ‘xyz’ or ‘jkl’.

Hence, the code is either ‘xyz abc opq’ or ‘jkl abc opq’.

Directions: Study the following information to answer the given questions.

In a certain code language,

‘She loves dog’ is coded as ‘ rst abc ptr’,

‘She likes travelling’ is coded as ‘bca ptr efg’,

‘Dog likes bone’ is coded as ‘mno rst bca’,

‘Ravi has dog’ is coded as ‘xyz jkl rst’.

Question:

35. If ‘Ravi’ is coded as ‘xyz’, then ‘ptr jkl ant act’ can be written as_________________.

A. He has a cat

B. She has a dog

C. Ravi has a cat

D. She has a pen

E. He has a pen

Solution

According to the information given,

Word for the code ‘ptr’: she.

Word for the code ‘rst’: dog.

Word for the code ‘bca’: likes.

Word for the code ‘abc’: loves.

Word for the code ‘efg’: traveling.

Word for the code ‘mno’: bone.

Here ‘has’ is coded as ‘jkl’.

Hence, the possible code is ‘She has a pen’.Question:

Directions: Read the following comprehension carefully and answer the questions given below.

A certain number of people are sitting in a linear row facing North. Two people are sitting between X and T. Only one person is sitting between T and M, who is not sitting to the left of T. M is sitting third to the right of S. Two people are sitting between M and Q, who is sitting third to the left of Y. P is sitting second to the left of S. P is sitting at the end of the row.

Question:

36. How many people are sitting in the row?

A. Eleven

B. Fourteen

C. Eighteen

D. Twelve

E. Fifteen

Solution

All are facing North.

1- Two people are sitting between X and T.

2- Only one person is sitting between T and M, who is not sitting to the left of T.

Case-1

Case-2

3- M is sitting third to the right of S.

4- Two people are sitting between M and Q, who is sitting third to the left of Y.

Case-1

Case-2

5- P is sitting second to the left of S. So case-1 gets eliminated.

So, Final arrangement is;

Twelve people are sitting in the row.

Directions: Read the following comprehension carefully and answer the questions given below.

Question:

37. What is the position of X with respect to Q?

A. Second to the right

B. Second to the left

C. Immediate left

D. Immediate right

E. Third to the left

Solution

All are facing North.

1- Two people are sitting between X and T.

2- Only one person is sitting between T and M, who is not sitting to the left of T.

Case-1

Case-2

3- M is sitting third to the right of S.

4- Two people are sitting between M and Q, who is sitting third to the left of Y.

Case-1

Case-2

5- P is sitting second to the left of S. So case-1 gets eliminated.

So, Final arrangement is;

X is second to the left of Q.

Directions: Read the following comprehension carefully and answer the questions given below.

Question:

38. If A is sitting in between T and M then who is sitting Fourth to the right of A?

A. P

B. Y

C. Q

D. X

E. S

Solution

All are facing North.

1- Two people are sitting between X and T.

2- Only one person is sitting between T and M, who is not sitting to the left of T.

Case-1

Case-2

3- M is sitting third to the right of S.

4- Two people are sitting between M and Q, who is sitting third to the left of Y.

Case-1

Case-2

5- P is sitting second to the left of S. So case-1 gets eliminated.

So, Final arrangement is;

If A is sitting in between T and M then Q is sitting Fourth to the right of A.

Directions: Read the following comprehension carefully and answer the questions given below.

Question:

39. Which of the following pair is sitting at extreme ends of the row?

A. Q,D

B. P,Y

C. M,X

D. X,Q

E. S,P

Solution

All are facing North.

1- Two people are sitting between X and T.

2- Only one person is sitting between T and M, who is not sitting to the left of T.

Case-1

Case-2

3- M is sitting third to the right of S.

4- Two people are sitting between M and Q, who is sitting third to the left of Y.

Case-1

Case-2

5- P is sitting second to the left of S. So case-1 gets eliminated.

So, Final arrangement is;

P,Y are sitting at extreme ends of the row.

Directions: Read the following comprehension carefully and answer the questions given below.

Question:

40. Who is sitting Immediate left of X?

A. P

B. Q

C. M

D. R

E. S

Solution

All are facing North.

1- Two people are sitting between X and T.

2- Only one person is sitting between T and M, who is not sitting to the left of T.

Case-1

Case-2

3- M is sitting third to the right of S.

4- Two people are sitting between M and Q, who is sitting third to the left of Y.

Case-1

Case-2

5- P is sitting second to the left of S. So case-1 gets eliminated.

So, Final arrangement is;

M is sitting Immediate left of X.

Numerical Ability

41.In the given question, two equations numbered I and II are given. Solve both the equations and mark the appropriate answer.

I. 5x + 536 = 576

II. 7y2 – 239 = 104

A. x < y

B. x > y

C. x ≤ y

D. x ≥ y

E. x = y or the relation between x and y can’t be established.

Solution

Given:

I. 5x + 536 = 576

II. 7y2 – 239 = 104

Calculation:

I. 5x + 536 = 576

⇒ 5x + 536 = 576

⇒ 5x = 576 – 536

⇒ 5x = 40

⇒ x = 40/5

⇒ x = 8

II. 7y2 – 239 = 104

⇒ 7y2 = 104 + 239

⇒ 7y2 = 343

⇒ y² = 343/7

⇒ y2 = 49

⇒ y = 7, (-7)

Value of ‘x’	Relation	Value of ‘y’
8	>	7
8	>	-7

When we compared the values of ‘x’ and ‘y’ in the table above, we found that there is only ONE relation between X and Y i.e. >. So, a relation between x and y is “x > y”.

∴ After comparison, all the values of x and y the relation is “x > y”.

42. In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. x² – 2x – 15 = 0

II. y² – 8y + 15 = 0

A. x > y

B. x < y

C. x ≥ y

D. x ≤ y

E. x = y or relation between x and y can not be established.

Solution

Calculation:

From I,

x2 – 2x – 15 = 0

⇒ x2 – 5x + 3x – 15 = 0

⇒ x(x – 5) + 3(x – 5) = 0

⇒ (x – 5)(x + 3) = 0

Taking,

⇒ (x – 5) = 0 or (x + 3) = 0

⇒ x = 5 or -3

From II,

y2 – 8y + 15 = 0

⇒ y2 – 3y – 5y + 15 = 0

⇒ y(y – 3) – 5(y – 3) = 0

⇒ (y – 3)(y – 5) = 0

Taking,

⇒ (y – 3) = 0 or (y – 5) = 0

⇒ y = 3 or 5

Comparison between x and y (via Tabulation):

Value of x	Value of y	Relation
5	3	x > y
5	5	x = y
-3	3	x < y
-3	5	x < y

∴ x = y or the relation between x and y can not be established.

43. In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. x²+ 2x – 48 = 0

II. y² = 196

A. x > y

B. x < y

C. x ≥ y

D. x ≤ y

E. No relation in x and y or x = y

Solution

Given:

I. x² + 2x – 48 = 0

II. y² = 196

Calculation:

From I

x² + 2x – 48 = 0

⇒ x² + 8x – 6x – 48 = 0

⇒ x(x + 8) – 6(x + 8) = 0

⇒ (x + 8)(x – 6) = 0

⇒ x = -8, 6

From II

y² = 196

⇒ y = ±14

Comparison between x and y (via Tabulation)

Value of x	Value of y	Relation between x & y
-8	14	x < y
-8	-14	x > y
6	14	x < y
6	-14	x > y

∴ No relation in x and y or x = y

Sign Method
Equation	Sign	Remark
ax² + bx + c = 0	-Ve, -Ve	Same signs
ax² – bx + c = 0	+Ve, +Ve	Same signs
ax² + bx – c = 0	-Ve, +Ve	Larger root is negative smaller root is positive
ax² – bx – c = 0	-Ve, +Ve	Larger root is positive smaller root is negative

44. In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. x = √36

II. y³ = 216

A. x > y

B. x < y

C. x ≥ y

D. x ≤ y

E. No relation in x and y or x = y

Solution

Given:

I. x = √36

II. y³ = 216

Calculation:

From I

x = √36

⇒ x = 6

From II

y³ = 216

⇒ y = 6

Comparison between x and y (via Tabulation)

Value of x	Value of y	Relation between x & y
6	6	x = y
6	6	x = y
6	6	x = y
6	6	x = y

∴ No relation in x and y or x = y

Sign Method
Equation	Sign	Remark
ax² + bx + c = 0	-Ve, -Ve	Same signs
ax² – bx + c = 0	+Ve, +Ve	Same signs
ax² + bx – c = 0	-Ve, +Ve	Larger root is negative smaller root is positive
ax² – bx – c = 0	-Ve, +Ve	Larger root is positive smaller root is negative

Mistake Points

All confuse between x = √36 and x² = 36

x = √36, x = 6 always as positive values

x2 = 36, x = +6, -6

45. In the given question, two equations numbered I and II are given. Solve both the equations and mark the appropriate answer.

I. x² + x – 182 = 0

II. y² – 29y + 210 = 0

A. x > y

B. x < y

C. x ≥ y

D. x ≤ y

E. x = y or relationship between x and y cannot be established

Solution

Given:

x2 + x – 182 = 0

y2 – 29y + 210 = 0

Calculation:

From I:

x2 + x – 182 = 0

⇒ x² + 14x – 13x – 182 = 0

⇒ x(x + 14) – 13(x + 14) = 0

⇒ (x + 14)(x – 13) = 0

⇒ x = -14, 13

From II:

y2 – 29y + 210 = 0

⇒ y² – 14y – 15y + 210 = 0

⇒ y(y – 14) – 15(y – 14) = 0

⇒ (y – 14)(y – 15) = 0

⇒ y = 14, 15

Comparison between x and y (via Tabulation):

Value of x	Value of y	Relation
-14	14	x < y
-14	15	x < y
13	14	x < y
13	15	x < y

∴ x < y.

46. The four numbers are in ratio 8 : 7 : 5 : 13. The difference between the largest and smallest number is 4800. What is the value of the smallest number?

A. 2000

B. 3000

C. 5000

D. 6000

E. 7000

Solution

Given:

The ratio of the four numbers is 8 : 7 : 5 : 13

Calculation:

Let the numbers be 8x, 7x, 5x and 13x

13x – 5x = 4800

⇒ 8x = 4800

⇒ x = 600

⇒ Smallest number = 5x

⇒ 5 × 600 = 3000

∴ The smallest number is 3000.

47. A person buys wine at the rate of Rs. 55 per litre. In what ratio the water should be mixed with wine so that he gains 20% on selling the mixture at Rs. 48 per litre?

A. 8 : 3

B. 3 : 8

C. 5 : 7

D. 7 : 5

E. 3 : 7

Solution

Formula Used:

Profit% = (SP – CP)/CP × 100

where, CP → Cost Price, SP → Selling Price

Calculations:

Let the quantity of wine and water added in final mixture be x and y respectively.

Cost price of wine = Rs. 55/litre

Cost price of water = Rs. 0/litre

Selling price after profit of 20% = Rs. 48/litre

⇒ Cost price of wine mixture = Rs. 48/(120/100) = Rs. 40

Now, 55 × x + 0y = (x + y) × 40

⇒ (55 – 40)x = 40y

⇒ 15x = 40y

⇒ x : y = 8 : 3

∴ The ratio in which water and wine should be mixed is 3 : 8.

Alternate Method

Cost price of wine = Rs. 55/litre

Cost price of water = Rs. 0/litre

Selling price after profit of 20% = Rs. 48/litre

⇒ Cost price of wine mixture = Rs. 48/(120/100) = Rs. 40

Using alligation,

Ratio of wine and water = 8 : 3

∴ The ratio in which water and wine should be mixed is 3 : 8.

Answer the questions from tabular chart shown below

The table mentioned below shows number of Christmas toys sold by company A, B, C and D.

Company	% of toys sold	% of toys returned as faulty (From total sold by that particular company)
A	30	10%
B	20	50%
C	25	25%
D	25	40%

Total number of toys sold considering all 4 companies is 6000.

48. Calculate total number of toys returned as faulty for company C

A. 500

B. 375

C. 425

D. 505

E. None of the above

Solution

Calculation:

Total number of toys = 6000

⇒ Toys sold by company C = 6000 × 0.25

⇒ Toys sold by company C = 1500

⇒ Toys returned as faulty = 25%

⇒ Toys returned as faulty = 1500 × 0.25

⇒ Toys returned as faulty = 375

∴ 375 toys were returned as faulty to company C

Answer the questions from tabular chart shown below

The table mentioned below shows number of Christmas toys sold by company A, B, C and D.

Company	% of toys sold	% of toys returned as faulty (From total sold by that particular company)
A	30	10%
B	20	50%
C	25	25%
D	25	40%

Total number of toys sold considering all 4 companies is 6000.

49. Calculate difference between number of toys returned as faulty to company B and Company C

A. 250

B. 375

C. 225

D. 300

E. None of the above

Solution

Calculation:

Total number of toys = 6000

⇒ Toys sold by company C = 6000 × 0.25

⇒ Toys sold by company C = 1500

⇒ Toys returned as faulty = 25%

⇒ Toys returned as faulty = 1500 × 0.25

⇒ Toys returned as faulty = 375

Toys sold by company B = 6000 × 0.20

⇒ Toys sold by company B = 1200

⇒ Toys returned to company B as faulty = 1200 × 0.5

⇒ Toys returned as faulty (Company B) = 600

⇒ required difference = 600 – 375

⇒ required difference = 225

∴ required difference is 225

Answer the questions from tabular chart shown below

The table mentioned below shows number of Christmas toys sold by company A, B, C and D.

Company	% of toys sold	% of toys returned as faulty (From total sold by that particular company)
A	30	10%
B	20	50%
C	25	25%
D	25	40%

Total number of toys sold considering all 4 companies is 6000.

50. Find the ratio of toys sold by company A to company D

A. 5 : 3

B. 5 : 6

C. 3 : 5

D. 3 : 7

E. 6 : 5

Solution

Calculation:

Total number of toys = 6000

⇒ Toys sold by company A = 6000 × 0.30

⇒ Toys sold by company A = 1800

Toys sold by company D = 6000 × 0.25

⇒ Toys sold by company D = 1500

⇒ required ratio = 1800: 1500

∴ required ratio is 6: 5

Answer the questions from tabular chart shown below

The table mentioned below shows number of Christmas toys sold by company A, B, C and D.

Company	% of toys sold	% of toys returned as faulty (From total sold by that particular company)
A	30	10%
B	20	50%
C	25	25%
D	25	40%

Total number of toys sold considering all 4 companies is 6000.

51. What is the average number of toys sold by company A, B and C?

A. 2500

B. 3750

C. 2250

D. 1500

E. None of the above

Solution

Calculation:

Total number of toys = 6000

⇒ Toys sold by company C = 6000 × 0.25

⇒ Toys sold by company C = 1500

⇒ Toys sold by company B = 6000 × 0.20

⇒ Toys sold by company B = 1200

⇒ Toys sold by company A = 6000 × 0.30

⇒ Toys sold by company A = 1800

⇒ Total of All 3 companies = 1500 + 1200 + 1800

⇒ Total = 4500

⇒ Average of all 3 companies = 4500 / 3

⇒ Average of all 3 companies = 1500

∴ required average is 1500

Answer the questions from tabular chart shown below

The table mentioned below shows number of Christmas toys sold by company A, B, C and D.

Company	% of toys sold	% of toys returned as faulty (From total sold by that particular company)
A	30	10%
B	20	50%
C	25	25%
D	25	40%

Total number of toys sold considering all 4 companies is 6000.

52. Which company observes least amount of faulty returns?

A. Company A

B. Company B

C. Company C

D. Company D

E. None of the above

Solution

Calculation:

Total number of toys = 6000

Toys sold by company C = 6000 × 0.25

⇒ Toys sold by company C = 1500

⇒ Toys returned as faulty = 25%

⇒ Toys returned as faulty = 1500 × 0.25

⇒ Toys returned as faulty (Company C) = 375

Toys sold by company B = 6000 × 0.20

⇒ Toys sold by company B = 1200

⇒ Toys returned to company B as faulty = 1200 × 0.5

⇒ Toys returned as faulty (Company B) = 600

Toys sold by company A = 6000 × 0.30

⇒ Toys sold by company A = 1800

⇒ Toys returned as faulty = 1800 × 0.10

⇒ Toys returned as faulty (Company A) = 180

Toys sold by company D = 6000 × 0.25

⇒ Toys sold by company D = 1500

⇒ Toys returned as faulty = 1500 × 0.40

⇒ Toys returned as faulty (Company D) = 600

∴ Company A observes least faulty returns

Note: This problem can be solved by just observing the values and computing it i.e., Company A and Company C has least % of faulty returns.

53. A man borrows a certain sum of money at simple interest for 8 years at 16% per annum. If the interest paid by him is Rs. 8000, then find the sum of money he borrows?

A. Rs. 6530

B. Rs. 6250

C. Rs. 6000

D. Rs. 7800

E. Rs. 6450

Solution

Given:

S.I. = Rs. 8000

Rate of interest, R = 16% per annum

Time, T = 8 years

Formula used:

S.I. = P × R% × T

Calculation:

Let the sum of money he borrows be Rs. P.

S.I. = P × R% × T

⇒ 8000 = P × 16/100 × 8

⇒ P = Rs. 6250

∴ The sum of money he borrows is Rs. 6250.

Was the solution helpful?Yes

54. A man travels first 288 km at a speed 64 km/hr, next 220 km at speed of 40 km/hr and rest of the 288 km at a speed of 48 km/hr. Find the average speed of man in the whole journey.

A. 49.75 km/hr

B. 40 km/hr

C. 55 km/hr

D. 42.25 km/hr

E. 45.5 km/hr

Solution

Given:

288 km distance travel by man with the speed of 64 km/hr.

220 km distance travel by man with the speed of 40 km/hr.

Rest 288 km distance travel by man with the speed of 48 km/hr.

Formula Used:

Time taken = Distance/ Speed

Average Speed = Total Distance Travelled/Total time taken

Calculation:

Time taken to cover 288 km with the speed of 64 km/hr = 288/64 = 4.5 hours

Time taken to cover 220 km with the speed of 40 km/hr = 220/40 = 5.5 hours

Time taken to cover 288 km with the speed of 48 km/hr = 288/48 = 6 hours

Total time taken = 4.5 + 5.5 + 6 = 16 hours

Total distance cover = 288 + 220 + 288 = 796 km

Average Speed = 796/16 = 49.75 km/hr

∴ Average speed of man in the whole journey is 49.75 km/hr.

55. P, Q and R are engaged to complete a task and earned Rs. 60,000. P and Q completes (5/8)th of the work together. Find the amount received by R.

A. Rs. 21,000

B. Rs. 21,500

C. Rs. 22,000

D. Rs. 22,500

E. Rs. 23,000

Solution

Given:

Total earnings = Rs. 60,000

Calculation:

Let the total work be 1

Then, share of R = [1 – (5/8)] × Rs. 60,000

⇒ [(8 – 5)/8] × Rs. 60,000

⇒ (3/8) × Rs. 60,000

⇒ Rs. 22,500

∴ Rs. 22,500 amount is received by R.

56. The number of visitors to Wankhede stadium increased by 30% during IPL. The price of ticket per match also increased by 20% then find the percentage of increase in revenue collection is:

A. 56%

B. 60%

C. 44%

D. 50%

E. None of these

Solution

Given

Increased the no. of visitors = 30%

Price of ticket increased by = 20%

Formula used

Successive Percentage = {x + y + (x × y)/100}

Calculation

Increased in the revenue = {30 + 20 + (20 × 30)/100}

⇒ 56%

∴ The increased in the revenue collection is 56%

57. What will come in the place of the question mark ‘?’ in the following question?

{(6/7) × 343} + {(5/8) × 512} = 500 + ?

A. 214

B. 114

C. 314

D. 414

E. None of these

Solution

Given:

{(6/7) × 343} + {(5/8) × 512} = 500 + ?

Concept used:

Follow the BODMAS rule according to the table given below:

Calculation:

{(6/7) × 343} + {(5/8) × 512} = 500 + ?

⇒ {6 × 49} + {5 × 64} = 500 + ?

⇒ 294 + 320 = 500 + ?

⇒ 614 = 500 + ?

⇒ ? = 614 – 500 = 114

∴ The value of ? will be 114.

58. What will come in the place of the question mark ‘?’ in the following question?

{∛(216) × 25} ÷ 30 – 40 = ? – 59

A. 14

B. 20

C. 34

D. 15

E. 24

Solution

Given:

{∛(216) × 25} ÷ 30 – 40 = ? – 59

Concept Used:

Follow the BODMAS rule according to the table given below:

Calculation:

{∛(216) × 25} ÷ 30 – 40 = ? – 59

⇒ {6 × 25} ÷ 30 – 40 + 59 = ?

⇒ 150 ÷ 30 – 40 + 59 = ?

⇒ 5 – 40 + 59 = ?

⇒ ? = 64 – 40 = 24

∴ 24 will come in place of the question mark (‘?’).

59. What will come in the place of the question mark ‘?’ in the following question?

(2¹² ÷ 2⁷) × 5 + 180 = ?% of 680

A. 50

B. 30

C. 60

D. 20

E. 40

Solution

Concept Used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

⇒ (212 ÷ 27) × 5 + 180 = ?% of 680

⇒ (2^{12 – 7}) × 5 + 180 = (?/100) × 680

⇒ 2⁵ × 5 + 180 = (?/10) × 68

⇒ 32 × 5 + 180 = (?/10) × 68

⇒ 160 + 180 = (?/10) × 68

⇒ 340 × (10/68) = ?

⇒ ? = 50

∴ The value of ? is 50

60. What will come in the place of the question mark ‘?’ in the following question?8.33% of 360 + 9.09% of 1331 = 10² + ?

A. 51

B. 41

C. 61

D. 31

E. 71

Solution

Given:

8.33% of 360 + 9.09% of 1331 = 10² + ?

Concept used:

Follow the BODMAS rule according to the table given below:

Calculation:

8.33% of 360 + 9.09% of 1331 = 10² + ?

⇒ (1/12) of 360 + (1/11) of 1331 = 10² + ?

⇒ 30 + 121 – 100 = ?

⇒ 151 – 100 = ?

⇒ ? = 51

∴ The value of ? will be 51.

Hint

Percentage to Fraction
100% = 1	25% = 1/4	14.28% = 1/7	10% = 1/10
50% = 1/2	20% = 1/5	12.50% = 1/8	9.09% = 1/11
33.33% = 1/3	16.66% = 1/6	11.11% = 1/9	8.33% = 1/12
7.69% =1/13	7.14% = 1/14	6.67% = 1/15	6.25% = 1/16
5.88% = 1/17	5.56% = 1/18	5.26% = 1/19	5% = 1/20

61. What will come in the place of the question mark ‘?’ in the following question?

62.5 × 16 + 1000 – (27)²+ (31)² = ?

A. 1232

B. 1032

C. 2132

D. 2232

E. None of these

Solution

Given:

62.5 × 16 + 1000 – (27)²+ (31)² = ?

Concept used:

Follow the BODMAS rule according to the table given below:

Calculation:

62.5 × 16 + 1000 – (27)²+ (31)² = ?

⇒ 1000 + 1000 – 729 + 961 = ?

⇒ 2000 + 961 – 729 = ?

⇒ 2961 – 729 = ?

⇒ 2232 = ?

∴ The value of ? is 2232.

62. If the length of a rectangle increases by 20% and the breadth of the rectangle reduces by 15%. What is the net percentage change in its area.

A. 1% increase

B. 1% decrease

C. 2% decrease

D. 2% increase

E. No percentage changed

Solution

Net percentage change in area of rectangle = 20 – 15 – [(20 × 15)/100]

⇒ 20 – 15 – 3

⇒ 2%

∴ The area of the rectangle increases by 2%.

Traditional Method:

Given:

Length of rectangle increases by 20%

Breadth of rectangle reduces by 15%

Formula used:

Area of a rectangle = Length × Breadth

and Percentage = (Favourable Value/Base value) × 100

Calculation:

Let the original length and breadth of the rectangle be x cmand y cm respectively.

Then, Area of the rectangle = x × y = xy cm²

New length = [1 + (20/100)] × x

⇒ (120/100) × x

⇒ 1.2x cm

and new breadth = [1 – (15/100)] × y

⇒ (85/100) × y

⇒ 0.85 y cm

So, New area of the rectangle = 1.2x × 0.85y

⇒ 1.02xy cm²

Difference in area = 1.02xy cm² – xy cm² = 0.02xy cm²

⇒ Net percentage change = [(0.02xy)/xy] × 100

⇒ 0.02 × 100

⇒ 2%

∴ The area of the rectangle increases by 2%.

63. A person marks his goods 30% above the cost price and gives a discount of 25% to the buyer on cash payment. Find the percentage of his profit or loss.

A. 1% loss

B. 2.5% loss

C. 3% loss

D. 2.5% profit

E. 3% profit

Solution

Given:

The price marked at = 30% higher

The discount = 25%

Formula used:

P = SP – CP

Where, P = Profit, SP = Selling price, and CP = Cost price

Calculation:

Let the cost price of goods be X

According to the question

The marked price = 1.3X

∴ The required result will be 2.5% loss.

Direction: Study the graph and answer the following questions.

64. What is the average run made by KKR in the year of 2009 and 2013 together?

A. 1250

B. 1400

C. 1650

D. 1090

E. 1600

Solution

Given:

The amount of run made by KKR in 2009 = 1200

The amount of run made by KKR in 2013 = 2000

Calculation:

Total run made by KKR in 2009 and 2013 together = (1200 + 2000) = 3200

∴ Required average = (3200 / 2) = 1600

Direction: Study the graph and answer the following questions.

65. What is the ratio between the total run made by MI and RCB together in 2011 and the total run made by KKR and RCB together in 2013?

A. 9 ∶ 8

B. 7 ∶ 9

C. 5 ∶ 7

D. 9 ∶ 10

E. None of the above

Solution

Given:

The amount of run made by MI in 2011 = 2400

The amount of run made by RCB in 2011 = 2100

The amount of run made by KKR in 2013 = 2000

The amount of run made by RCB in 2013 = 3000

Calculation:

Total run made MI and RCB in 2011 together = (2400 + 2100) = 4500

Total run made by KKR and RCB in 2013 together = (2000 + 3000) = 5000

∴ Required ratio = 4500 ∶ 5000 = 9 ∶ 10

Direction: Study the graph and answer the following questions.

66. What is the difference between the total runs made by three teams in 2015 and the total runs made by three teams in 2011?

A. 1250

B. 1000

C. 1100

D. 1300

E. 860

Solution

Given:

The amount of run made by KKR in 2015 = 2200

The amount of run made by MI in 2015 = 2500

The amount of run made by RCB in 2015 = 2600

The amount of run made by KKR in 2011 = 1800

The amount of run made by MI in 2011 = 2400

The amount of run made by RCB in 2011 = 2100

Calculation:

Total run made by three teams in 2015 = (2200 + 2500 + 2600) = 7300

Total run made by three teams in 2011 = (1800 + 2400 + 2100) = 6300

∴ Difference = (7300 − 6300) = 1000

Direction: Study the graph and answer the following questions.

67. If two-seventh part of the total run of RCB is scored by Kohli in 2011, how many run did Kohli scored in 2011?

A. 1000

B. 750

C. 600

D. 350

E. 500

Solution

Given:

The amount of run made by RCB in 2011 = 2100

The part of total run made by RCB from there Kohli scored = 2 / 7

Calculation:∴ Kohli scored = (2100 × 2 / 7) = 600

Direction: Study the graph and answer the following questions.

68. What is the total number of run scored by KKR and RCB in four years together?

A. 11250

B. 12500

C. 18400

D. 16600

E. 20000

Solution

Given:

Run made by KKR in 2009 = 1200

Run made by KKR in 2011 = 1800

Run made by KKR in 2013 = 2000

Run made by KKR in 2015 = 2200

Run made by RCB in 2009 = 1700

Run made by RCB in 2011 =2100

Run made by RCB in 2013 = 3000

Run made by RCB in 2015 = 2600

Calculation:

Total run made by KKR and RCB in four years together = (1200 + 1800 + 2000 + 2200 + 1700 + 2100 + 3000 + 2600) = 16600

69. A thief runs a certain distance with a speed of 12 km/h in 16 min. If he wants to cover the same distance in 12 min, what should be his speed?

A. 14 km/hr

B. 16 km/hr

C. 10 km/hr

D. 12 km/hr

E. None of these

Solution

Given:

Speed of the thief (s₁) = 12 km/h

Time to take cover the distance (t₁) = 16 min = 16/60 hr

Time to take cover the distance (t₂) = 12 min = 12/60 hr

Concept used:

Speed = Distance/Time

Time = 1/speed —-(When distance is equal)

Calculation:

Let, the speed of the thief to cover the same distance in 12 min be s₂

According to the question,

⇒ s₁ × t₁ = s₂ × t₂

⇒ 12 × (16/60) = s₂ × (12/60)

⇒ s₂ = 16

∴ The speed of the thief to cover the same distance in 12 min is 16 km/hr

70. 7 boys and 10 girls can do a piece of work in 12 days. 5 boys and 8 girls can do the same work in 16 days. In how many days can 3 boys and 6 girls complete the work?

A. 28

B. 30

C. 24

D. 32

E. None of these

Solution

Given:

7B + 10G complete the work in 12 days

5B + 8G complete the work in 16 days

Formula:

Person₁× Days₁= Person₂× D₂

Calculations:

Let efficiency of one Boy and Girls be B and G respectively

We know that, P₁D₁= P₂D₂

Given that, (7B + 10G)12 = (5B + 8G)16

⇒ 21B + 30G = 20B + 32G

⇒ 1B = 2G …… sub in P₁D₁(or) P₂D₂

⇒ 7B + 10G = 7 × 2G + 10G = 24 girls will complete the work in 12 days.

Now, 3B + 6G = 3 × 2G + 6G = 12 girls

⇒ P₁D₁= P₂D₂

⇒ 24 × 12 = 12 × D₂

⇒ D₂ = 24

∴ 3 boys and 6 girls can complete the work in 24 days.

71. What should come in place of the question mark (?) in the following number series?

113, 225, 449, ?, 1793

A. 789

B. 786

C. 897

D. 987

E. None of these

Solution

113 × 2 – 1 = 225

225 × 2 – 1 = 449

449 × 2 – 1 = 897

897 × 2 – 1 = 1793

72. What should come in place of the question mark ‘?’ in the following number series?1, 3, 7, ?, 31, 63, 127

A. 3

B. 15

C. 11

D. 20

E. 6

Solution

1 × 2 + 1 = 3

3 × 2 + 1 = 7

7 × 2 + 1 = 15

15 × 2 + 1 = 31

31 × 2 + 1 = 63

63 × 2 + 1 = 127

∴ ? = 15

Was the solution helpful?

73. What should come in place of the question mark ‘?’ in the following number series?

180, 174, 162, 144, 120, ?

A. 50

B. 60

C. 70

D. 80

E. 90

Solution

Considering the above series,

180, 174, 162, 144, 120, ?

The logic of the series can be explained as,

180 – (6 × 1) = 174

174 – (6 × 2) = 162

162 – (6 × 3) = 144

144 – (6 × 4) = 120

By observing the pattern, we can write

120 – (6 × 5) = 90

⇒ ? = 90

∴ The value of ? is 90.

74. What should come in place of question mark ‘?’ in the following number series?

8, 9, 11, 13, 14, 17, 17, ?

A. 20

B. 21

C. 22

D. 23

E. 24

Solution

Considering the above series,

8, 9, 11, 13, 14, 17, 17, ?

The logic of the series can be explained as,

11 – 8 = 3

14 – 11 = 3

17 – 14 = 3

13 – 9 = 4

17 – 13 = 4

By observing the pattern, we can write

? – 17 = 4

⇒ ? = 21

∴ The value of ? is 21.

75. What should come in place of the question mark ‘?’ in the following number series?

200, 190, ?, 140, 100, 50, -10

A. 170

B. 180

C. 185

D. 175

E. 150

Solution

Calculation:

The series follows following pattern:

⇒ 200

⇒ 200 – 10 = 190

⇒ 190 – 20 = 170

⇒ 170 – 30 = 140

⇒ 140 – 40 = 100

⇒ 100 – 50 = 50

⇒ 50 – 60 = -10

∴ The value of ? is 170

Comprehension:(Que No. 36 – 40)

Directions: Study the following data and answer the following questions.Total of 900 customers visited the shop. 520 customers bought Blue pens and 270 customers bought both red and blue pens. 490 customers bought Red pens. Some customers didn’t buy any pens.

76. Find the average number of customers who bought only Red and only Blue pens.

A. 235

B. 260

C. 290

D. 220

E. 240

Solution

Given:

Total number of customers of a shop = 900

Total number of customers who bought both pens = 270

Total number of customers who bought only Blue pens = 520 – 270 = 250

Total number of customers who bought only Red pens = 490 – 270 = 220

Required average =

= (250 + 220)/2

= 235

Comprehension:(Que No. 36 – 40)

77. The number of customers who didn’t buy any pen is approx. what percent of the total number of customers of the shop?

A. 18%

B. 20%

C. 11%

D. 12%

E. 14%

Solution

Given:

Total number of customers of a shop = 900

Total number of customers who bought both pens = 270

⇒ Total number of customers who bought only Blue pens = 520 – 270 = 250

⇒ Total number of customers who bought only Red pens = 490 – 270 = 220

⇒ Total number of customers who didn’t bought any pen = 900 – 270 – 250 – 220 = 160

⇒ Required percentage = 160/900 × 100

⇒ Required percentage = 17.77% ~ 17% as approx

78. Find the ratio between the number of customers who bought both pens and who didn’t buy any pen.

A. 16 : 27

B. 27 : 19

C. 19 : 16

D. 27 : 16

E. 16 : 19

Solution

Given:

Total number of customers of a shop = 900

Total number of customers who bought both pens = 270

⇒ Total number of customers who bought only Blue pens = 520 – 270 = 250

⇒ Total number of customers who bought only Red pens = 490 – 270 = 220

⇒ Total number of customers who didn’t bought any pen = 900 – 270 – 250 – 220 = 160

⇒ Required ratio = 270 : 160

= 27 : 16

79. Find the difference between the number of customers who bought at least one pen and a number of customers who bought at most one pen.

A. 120

B. 160

C. 80

D. 135

E. 110

Solution

Given:

Total number of customers of a shop = 900

Total number of customers who bought both pens = 270

⇒ Total number of customers who bought only Blue pens = 520 – 270 = 250

⇒ Total number of customers who bought only Red pens = 490 – 270 = 220

⇒ Total number of customers who didn’t bought any pen = 900 – 270 – 250 – 220 = 160

⇒ Number of customers who bought at least one pen = 250 + 220 + 270 = 740

⇒ Number of customers who bought at most one pen = 250 + 220 + 160 = 630

⇒ Required difference = 740 – 630 = 110

80. The number of customers who bought only one pen is approximately what percent more than the number of customers who bought both pens?

A. 83%

B. 74%

C. 82%

D. 90%

E. 88%

Solution

Given:

Total number of customers of a shop = 900

Total number of customers who bought both pens = 270

⇒ Total number of customers who bought only Blue pens = 520 – 270 = 250

⇒ Total number of customers who bought only Red pens = 490 – 270 = 220

⇒ Total number of customers who bought only one pen = 250 + 220 = 470

⇒ Required percentage = (470-270)/270× 100%

⇒ Required percentage = (200)/270 × 100%

⇒ Required percentage = 74%

IBPS RRB Clerk Prelims Full Test 4

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