IBPS RRB Clerk Prelims Full Test 9

Direction: Study the following information to answer the given questions: Eight persons M, N, O, P, Q, R, S and T are sitting around the circular table facing towards the center. M sits third to the right of N. R sits adjacent to M. O sits second to the right of R. P is not adjacent to R. S sits opposite to P. T is adjacent to neither Q nor N.

1.Who sits immediate left of N?

A. P

B. T

C. R

D. Q

E. S

Solution

Persons: M, N, O, P, Q, R, S and T.

1) M sits third to the right of N.

2) R sits adjacent to M.

3) O sits second to the right of R.

4) S sits opposite to P.

5) P is not adjacent to R.

6) T is adjacent to neither Q nor N. So, case 2 would be invalid as it contradicts the given point.

Hence, Q sits immediate left of N.

2. How many persons sit between S and T when counted from the left of S?

A. Three

B. Two

C. Four

D. One

E. Five

Solution

Persons: M, N, O, P, Q, R, S and T.

1) M sits third to the right of N.

2) R sits adjacent to M.

3) O sits second to the right of R.

4) S sits opposite to P.

5) P is not adjacent to R.

6) T is adjacent to neither Q nor N. So, case 2 would be invalid as it contradicts the given point.

Hence, two persons sit between S and T when counted from the left of S.

3. ______ sits third to the left of O.

A. Q

B. S

C. T

D. P

E. M

Solution

Persons: M, N, O, P, Q, R, S and T.

1) M sits third to the right of N.

2) R sits adjacent to M.

3) O sits second to the right of R.

4) S sits opposite to P.

5) P is not adjacent to R.

6) T is adjacent to neither Q nor N. So, case 2 would be invalid as it contradicts the given point.

Hence, M sits third to the left of O.

4. Who sits opposite to R?

A. N

B. O

C. Q

D. M

E. T

Solution

Persons: M, N, O, P, Q, R, S and T.

1) M sits third to the right of N.

2) R sits adjacent to M.

3) O sits second to the right of R.

4) S sits opposite to P.

5) P is not adjacent to R.

6) T is adjacent to neither Q nor N. So, case 2 would be invalid as it contradicts the given point.

Hence, N sits opposite to R.

5. Which of the following statement is correct?

A. O sits opposite to P

B. M sits immediate right of T

C. Q sits second to the left of M

D. S sits immediate left of Q

E. All are correct

Solution

Persons: M, N, O, P, Q, R, S and T.

1) M sits third to the right of N.

2) R sits adjacent to M.

3) O sits second to the right of R.

4) S sits opposite to P.

5) P is not adjacent to R.

6) T is adjacent to neither Q nor N. So, case 2 would be invalid as it contradicts the given point.

Hence, only statement 2) is correct.

Direction: Study the given information carefully and answer the following questions.Seven trees M, N, O, P, Q, R and S were planted in a garden. Tree O is 8m north of tree S. Tree S is 7m west of tree M. Tree M is 13m east of tree R. Tree R is 15m south of tree N. Tree N is 5m east of tree P. Tree P is 7m east of tree Q.

6. What is the distance between Tree R and Tree S?

A. 14m

B. 8m

C. 7m

D. 13m

E. 6m

Solution

Drawing diagram according to the given information:

Hence, the distance between tree R and tree S is 6m.

7. Tree M is in which direction with respect to Tree N?

A. East

B. South west

C. North east

D. North west

E. South east

Solution

Drawing diagram according to the given information:

Hence, tree M is in south east direction with respect to tree N.

8. If tree T is 8m north of tree R, then what will be the distance between treen N and tree T?

A. 9m

B. 15m

C. 12m

D. 7m

E. 8m

Solution

Drawing diagram according to the given information:

Drawing diagram according to the given information:

Hence, the distance between tree N and tree T will be 7m.

9. Direction: In the question below are given three statements followed by two conclusions numbered I and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.

Statements:

Some house are home.

Some home are shop.

Some shop are grocery.

Conclusions:

I. All home are shop.

II. Some shop are not home.

A. None follows

B. Either I or II follows

C. Only I follows

D. Only II follows

E. Both I and II follow

Solution

The least possible venn diagram for the given statements is as follows:

Conclusion:

I. All home are shop → False (It is possible but not definite)

II. Some shop are not home → False (It is possible but not definite)

Hence, None follows.

10. Direction: In the question below are given three statements followed by two conclusions numbered I and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.

Statements:

All car are bike.

All bike are cycle.

Some bike are bus.

Conclusions:

I. All bus being cycle is a possibility.

II. No car is a bus.

A. None follows

B. Either I or II follows

C. Only I follows

D. Only II follows

E. Both I and II follow

Solution

The least possible venn diagram for the given statements is as follows:

Conclusion:

I. All bus being cycle is a possibility → True (Possibility is true as shown below)

II. No car is a bus → False (It is possible but not definite)

Hence, only I follows.

11. Direction: In the question below are given three statements followed by two conclusions numbered I and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.

Statements:

Some movie are film.

Some film are best.

Some best are documentary.

Conclusions:

I. Some documentary are not movie.

II. All film are documentary.

A. None follows

B. Either I or II follows

C. Only I follows

D. Only II follows

E. Both I and II follow

Solution

The least possible venn diagram for the given statements is as follows:

Conclusions:

I. Some documentary are not movie → False (It is possible but not definite)

II. All film are documentary → False (It is possible but not definite)

Hence, none follows

Direction: Study the following information to answer the given questions:

There are 8 floors in a building. Seven persons M, N, O, P, Q, R, and S live on seven different floors of the building. One floor is vacant i. e. no one lives on that floor. The lowermost floor is numbered as 1, the floor above it as 2, and so on. Neither the lowermost nor topmost floor is vacant.Only one person lives below P’s floor. N lives two floors above P’s floor. O lives on floor 6. S lives just above M’s floor. R does not live adjacent to N’s floor. The number of floors below Q’s floor is half of the number of persons living above him.

12. Who lives on topmost floor?

A. M

B. N

C. Q

D. R

E. S

Solution

Persons: M, N, O, P, Q, R, and S.

1) O lives on floor 6.

2) Only one person lives below P’s floor. So, P lives on either floor 2 or floor 3.

3) N lives two floors above P’s floor.

4) Neither the lowermost nor topmost floor is vacant. So, in case 2, floor 2 would be vacant.

	Case 1	Case 2
Floor	Person	Person
8
7
6	O	O
5		N
4	N
3		P
2	P	Vacant
1

5) S lives just above M’s floor.

6) R does not live adjacent to N’s floor. So, R lives on floor 1.

	Case 1	Case 2
Floor	Person	Person
8	S	S
7	M	M
6	O	O
5		N
4	N	Q
3		P
2	P	Vacant
1	R	R

7) Number of floors below Q’s floor is half of the number of persons living above him. So, case 2 would be invalid as it contradicts the given statement. Also, in case 1, floor 5 would be vacant and Q lives on floor 3.

Floor	Person
8	S
7	M
6	O
5	Vacant
4	N
3	Q
2	P
1	R

Hence, S lives on the topmost floor.

13. How many persons live above N’s floor?

A. Three

B. Four

C. Five

D. Two

E. One

Solution

Persons: M, N, O, P, Q, R, and S.

1) O lives on floor 6.

2) Only one person lives below P’s floor. So, P lives on either floor 2 or floor 3.

3) N lives two floors above P’s floor.

4) Neither the lowermost nor topmost floor is vacant. So, in case 2, floor 2 would be vacant.

	Case 1	Case 2
Floor	Person	Person
8
7
6	O	O
5		N
4	N
3		P
2	P	Vacant
1

5) S lives just above M’s floor.

6) R does not live adjacent to N’s floor. So, R lives on floor 1.

	Case 1	Case 2
Floor	Person	Person
8	S	S
7	M	M
6	O	O
5		N
4	N	Q
3		P
2	P	Vacant
1	R	R

Floor	Person
8	S
7	M
6	O
5	Vacant
4	N
3	Q
2	P
1	R

Hence, three persons live above N’s floor.

14. Four are the same in a certain way thus forms a group. Which among the following does not belong to the group?

A. N

B. Q

C. O

D. P

E. S

Solution

Persons: M, N, O, P, Q, R, and S.

1) O lives on floor 6.

2) Only one person lives below P’s floor. So, P lives on either floor 2 or floor 3.

3) N lives two floors above P’s floor.

4) Neither the lowermost nor topmost floor is vacant. So, in case 2, floor 2 would be vacant.

	Case 1	Case 2
Floor	Person	Person
8
7
6	O	O
5		N
4	N
3		P
2	P	Vacant
1

5) S lives just above M’s floor.

6) R does not live adjacent to N’s floor. So, R lives on floor 1.

	Case 1	Case 2
Floor	Person	Person
8	S	S
7	M	M
6	O	O
5		N
4	N	Q
3		P
2	P	Vacant
1	R	R

Floor	Person
8	S
7	M
6	O
5	Vacant
4	N
3	Q
2	P
1	R

All N, O, P and S live on the even-numbered floors except Q.

Hence, Q does not belong to the group.

15. Who lives just above R’s floor?

A. Q

B. P

C. S

D. M

E. O

Solution

Persons: M, N, O, P, Q, R, and S.

1) O lives on floor 6.

2) Only one person lives below P’s floor. So, P lives on either floor 2 or floor 3.

3) N lives two floors above P’s floor.

4) Neither the lowermost nor topmost floor is vacant. So, in case 2, floor 2 would be vacant.

	Case 1	Case 2
Floor	Person	Person
8
7
6	O	O
5		N
4	N
3		P
2	P	Vacant
1

5) S lives just above M’s floor.

6) R does not live adjacent to N’s floor. So, R lives on floor 1.

	Case 1	Case 2
Floor	Person	Person
8	S	S
7	M	M
6	O	O
5		N
4	N	Q
3		P
2	P	Vacant
1	R	R

Floor	Person
8	S
7	M
6	O
5	Vacant
4	N
3	Q
2	P
1	R

Hence, “P” lives just above R’s floor.

16. Which of the following statement is correct?

A. M lives on floor 5

B. N lives on odd numbered floor

C. P lives just above Q’s floor

D. Floor 5 is a vacant floor

E. All are correct

Solution

Persons: M, N, O, P, Q, R, and S.

1) O lives on floor 6.

2) Only one person lives below P’s floor. So, P lives on either floor 2 or floor 3.

3) N lives two floors above P’s floor.

4) Neither the lowermost nor topmost floor is vacant. So, in case 2, floor 2 would be vacant.

	Case 1	Case 2
Floor	Person	Person
8
7
6	O	O
5		N
4	N
3		P
2	P	Vacant
1

5) S lives just above M’s floor.

6) R does not live adjacent to N’s floor. So, R lives on floor 1.

	Case 1	Case 2
Floor	Person	Person
8	S	S
7	M	M
6	O	O
5		N
4	N	Q
3		P
2	P	Vacant
1	R	R

Floor	Person
8	S
7	M
6	O
5	Vacant
4	N
3	Q
2	P
1	R

Thus, floor 5 is a vacant floor statement is correct.

Hence, “Option (4)” is the correct answer.

17. How many pairs of digits are there in the given number, that have as many numbers between them as in the series of natural numbers both in the backward and forward direction?

69431852

A. Four

B. One

C. Three

D. Two

E. Seven

Solution

Given number: 69431852

Thus, we get three pairs,

Backward → (3, 4), (3, 6), (4, 6)

Hence, three is the correct answer.

Comprehension:(Que No. 18 – 21)

Directions: Study the following information carefully and answer the given questions.

In a certain language,

“make him your senior partner” is coded as “kpa lpa bpa opa spa”

“harvey make mike smile” is coded as “dpa lpa tpa fpa”

“his partner harvey” is coded as “tpa spa cpa”“your smile matters” is coded as “xpa fpa opa”.

18. What is the code for “matters”?

A. xpa

B. cpa

C. fpa

D. opa

E. cannot be determined

Solution

The words are coded as given below:

Hence, “matters” will be coded as ‘xpa’.

19. What is the code for “mike?

A. kpa

B. dpa

C. fpa

D. tpa

E. Cannot be determined

Solution

The words are coded as given below:

Hence, the code for ‘mike’ is ‘dpa’.

20. What is the code for “senior”?

A. kpa

B. bpa

C. Either (1) or (2)

D. spa

E. cannot be determined

Solution

The words are coded as given below:

Hence, ‘senior’ will be coded as either ‘kpa’ or ‘bpa’.

21. What is the code for “his”?

A. tpa

B. spa

C. fpa

D. cpa

E. none of these

Solution

The words are coded as given below:

Hence, “his” will be coded as ‘cpa’.

Direction: On the basis of the alphabets given below, answer the following questions:

T R G S O I W P A Q D V E U X Z B Y C H F

22. How many such consonants are there in the above series, each of which is immediately preceded by a vowel and followed by a consonant?

A. Three

B. Two

C. One

D. Five

E. Six

Solution

Given series: Left side T R G S O I W P A Q D V E U X Z B Y C H F Right side

Such consonants that are immediately preceded by a vowel and followed by a consonant are:

T R G S O I W P A Q D V E U X Z B Y C H F

Thus, three consonants are immediately preceded by a vowel and followed by a consonant.

Hence, Three is the correct answer.

23. In the above alphabets, if each letter starting from S, is represented by the day of the week starting from Sunday, then what is the position of first occurring Sunday from the right?

A. Sixth

B. Seventh

C. Third

D. Eighth

E. Fourth

Solution

Let Sunday be represented by Su, Monday be Mo, Tuesday be Tu, Wednesday be We, Thursday be Th, Friday be Fr, Saturday be Sa in the following table.

Each letter starting from S is represented by the day of the week starting from Sunday:

Alphabet

Day

Hence, the position of first occurring Sunday from right is fourth.

23. How many such vowels are there in the above series, each of which is immediately preceded by a vowel and followed by a consonant?

A. Three

B. One

C. Two

D. Five

E. Six

Solution

Given series: Left side T R G S O I W P A Q D V E U X Z B Y C H F Right side

Such vowels that are immediately preceded by a vowel and followed by a consonant are:

T R G S O I W P A Q D V E U X Z B Y C H FHence, two vowels are immediately preceded by a vowel and followed by a consonant.

24. If all the vowels are dropped from the above arrangement, which letter will be the fourth letter to the left of the ninth letter from the left end?

A. P

B. W

C. A

D. I

E. S

Solution

Given series: Left side T R G S O I W P A Q D V E U X Z B Y C H F Right side

If all the vowels are dropped, the new series will be:

Left side T R G S W P Q D V X Z B Y C H F Right side

The ninth letter from the left side is V. T R G S W P Q D V X Z B Y C H F

The fourth letter to the left of V is W. T R G S W P Q D V

Hence, W is the correct answer.

25. If all the vowels are dropped from the above arrangement, which letter will be the fourth letter to the left of the ninth letter from the left end?

A. P

B. W

C. A

D. I

E. S

Solution

Given series: Left side T R G S O I W P A Q D V E U X Z B Y C H F Right side

If all the vowels are dropped, the new series will be:

Left side T R G S W P Q D V X Z B Y C H F Right side

The ninth letter from the left side is V. T R G S W P Q D V X Z B Y C H F

The fourth letter to the left of V is W. T R G S W P Q D V

Hence, W is the correct answer.

26. In the following letter series, which will replace the question mark (?)?PQD, IVQ, SUA, ?, FYW

A. RSO

B. TGS

C. SPE

D. RZP

E. QUX

Solution

Given series: Left side T R G S O I W P A Q D V E U X Z B Y C H F Right side

1) First letters are forming different series:

P – 2 = I

I – 2 = S

S – 2 = R

R – 2 = F

2) Secondletters are forming different series:

Q + 2 = V

V + 2 = U

U + 2 = Z

Z + 2 = Y

3) Third letters are forming different series:

D – 1 = Q

Q – 1 = A

A – 1 = P

P – 1 = WHence, the word formed is RZP.

27. Direction:In the following question assuming the given statements to be True, find which of the conclusion among given conclusions is/are definitely true and then give your answers accordingly.

Statements:

L > M ≥ O; N = E ≤ M

Conclusions:

I. L > NII. E < L

A. Only II is true

B. Only I is true

C. Both I and II are true

D. Either I or II is true

E. None is true

Solution

Given Statements: L > M ≥ O; N = E ≤ M

On Combining: L > M ≥ E = N; N = E ≤ M ≥ O

Conclusions:

I. L > N → True (As, L > M ≥ E = N → L > N = E or E = N < L)

II. E < L → True (As, L > M ≥ E = N → L > E = N or N = E < L)

Hence, both the conclusions are true

28. Direction:In the following question assuming the given statements to be True, find which of the conclusion among given conclusions is/are definitely true and then give your answers accordingly.

Statements:

W ≥ Z = B < O; B < F ≤ Q

Conclusions:

I. Q > Z

II. B = Q

A. Only II is true

B. Only I is true

C. Both I and II are true

D. Either I or II is true

E. None is true

Solution

Given Statements: W ≥ Z = B < O; B < F ≤ Q

On Combining: W ≥ Z = B < F ≤ Q; Q ≥ F > Z = B < O

Conclusions:

I. Q > Z → True (As, Q ≥ F > Z = B < O → Q > Z = B)

II. B = Q → False (As, Q ≥ F > Z = B < O → Q > Z = B)

Hence, only conclusion I is true

29. Direction:In the following question assuming the given statements to be True, find which of the conclusion among given conclusions is/are definitely true and then give your answers accordingly.

Statements:

L > J > M; M = H; J < O = P

Conclusions:

I. H < O

II. J ≥ M

A. Only II is true

B. Only I is true

C. Both I and II are true

D. Either I or II is true

E. None is true

Solution

Given Statements: L > J > M; M = H; J < O = P

On Combining: P = O > J > M = H; L > J < O = P

Conclusions:

I. H < O → True (As, P = O > J > M = H → O > H or H < O)

II. J ≥ M → False (As, J > M or M < J)

Hence, only conclusion I is true.

Directions: Study the given information and answer the questions that follows:

There are 6 friends and their names are Aniket, Bankim, Chinmay, Dhruv, Ekansh and Farooq. Each of them have different heights.

Farooq is second tallest among all while Bankim is not the shortest. Chinmay is taller than Dhruv and Aniket but shorter than Farooq. Aniket is taller than only one person who is definitely not Dhruv.

30. Who is the tallest among all six friends?

A. Bankim

B. Aniket

C. Chinmay

D. Dhruv

E. Ekansh

Solution

1. Farooq is second tallest among all.

____> Farooq > ____ > ____ > ____ > ____

2. Aniket is taller than only one person.

____> Farooq > ____ >____ >Aniket ____

3. Chinmay is taller than Dhruv and Aniket but shorter than Farooq.

4. Aniket is taller than only person who is definitely not Dhruv.

____ > Farooq > Chinmay > Dhruv > Aniket > ____

5. Bankim is not the shortest.

Bankim > Farooq > Chinmay > Dhruv > Aniket > Ekansh

Hence, Bankim is the tallest among all.

31. How many people are taller than Aniket?

A. 1

B. 2

C. 3

D. 4

E. None

Solution

1. Farooq is second tallest among all.

____> Farooq > ____ > ____ > ____ > ____

2. Aniket is taller than only one person.

____> Farooq > ____ >____ >Aniket ____

3. Chinmay is taller than Dhruv and Aniket but shorter than Farooq.

4. Aniket is taller than only person who is definitely not Dhruv.

____ > Farooq > Chinmay > Dhruv > Aniket > ____

5. Bankim is not the shortest.

Bankim > Farooq > Chinmay > Dhruv > Aniket > Ekansh

Hence, 4 people are taller than Aniket.

32. Who is/are taller than Dhruv but shorter than Bankim?

A. Aniket

B. Chinmay

C. Farooq

D. Aniket and Chinmay both

E. Chinmay and Farooq both

Solution

1. Farooq is second tallest among all.

____> Farooq > ____ > ____ > ____ > ____

2. Aniket is taller than only one person.

____> Farooq > ____ >____ >Aniket ____

3. Chinmay is taller than Dhruv and Aniket but shorter than Farooq.

4. Aniket is taller than only person who is definitely not Dhruv.

____ > Farooq > Chinmay > Dhruv > Aniket > ____

5. Bankim is not the shortest.

Bankim > Farooq > Chinmay > Dhruv > Aniket > Ekansh

Hence, Chinamy and Farooq both are taller than Dhruv but shorter than Bankim.

Direction: Study the following information carefully and answer the below questions

A family consists of seven members and two married couples. Either both the parents of a person are alive or neither of them is alive. B is the father-in-law of O. P is the brother-in-law of O. O and P has same gender. S is the only daughter of V, who is the maternal grandmother of H. P has only one brother. H is the niece of G.

33. How G is related to S?

A. Sister

B. Brother

C. Sister-in-law

D. Brother-in-law

E. Can’t be determined

Solution

As per the given information,

1)B is the father-in-law of O.

2) P is the brother-in-law of O. O and P has same gender.

3) S is the only daughter of V, who is the maternal grandmother of H.

4) P has only one brother. H is the niece of G.

Hence, G is the brother of S.

34. Which of the following statement is true?

A. B has only one son

B. V is the mother-in-law of P

C. V has three children

D. H is the only son of O

E. None of the above

Solution

As per the given information,

1)B is the father-in-law of O.

2) P is the brother-in-law of O. O and P has same gender.

3) S is the only daughter of V, who is the maternal grandmother of H.

4) P has only one brother. H is the niece of G.

Hence, V has three children is the correct answer.

35. Who among the following is Uncle of H?

A. G

B. P

C. S

D. B

E. Both G and P

Solution

As per the given information,

1)B is the father-in-law of O.

2) P is the brother-in-law of O. O and P has same gender.

3) S is the only daughter of V, who is the maternal grandmother of H.

4) P has only one brother. H is the niece of G.

Hence, Both G and P are the uncles of H.

Direction: Study the following information carefully and answer the questions given below.

In an organisation, there are eight persons Sanju, Jay, Athul, Gopu, Aswin, Raghu, Kripa, and Rahul went to tour on three different tourist spots. The tourist spots are Paris, Kashmir, and New York. At least two persons went to a tourist spot and at most three persons went to a tourist spot.

Athul and Kripa went on tour together to the same place. Rahul doesn’t go to Paris. Gopu doesn’t go to Kashmir. Gopu went on tour with Rahul to the same place. More than two people went on tour to Paris. Jay went on tour with two other people but not in New York. Sanju went on tour with Raghu only.

36. Who among the following went to Paris?

A. Kripa

B. Jay

C. Athul

D. All of the above

E. None of the above

Solution

Given Details

Eight persons Sanju, Jay, Athul, Gopu, Aswin, Raghu, Kripa, and Rahul.

The tourist spots are Paris, Kashmir, and New York.

At least two persons went to a tourist spot and at most three persons went to a tourist spot.

Gopu doesn’t go to Kashmir.

Gopu went on tour with Rahul to the same place.

Rahul doesn’t go to Paris.

From these, we get that Gopu and Rahul went to New York.

Tourist Spot	Names of People
Paris
Kashmir
New York	Gopu, Rahul

Sanju went on tour with Raghu only.

More than two people went on tour to Paris.

From these we get, Sanju and Raghu went tour to Kashmir

Tourist Spot	Names of People
Paris
Kashmir	Sanju, Raghu
New York	Gopu, Rahul

Jay went on tour with two other people but not in New York.

Athul and Kripa went on tour together to the same place.

From these, we get that Jay went with Athul and Kripa to Paris while Aswin went to New York.

Final arrangement.

Tourist Spot	Names of People
Paris	Athul, Jay, Kripa
Kashmir	Sanju, Raghu
New York	Gopu, Rahul, Aswin

From the final arrangement we get, Athul, Jay, and Kripa went tour to Paris. So the answer is All of the above.

37. Which touring spot was chosen by Gopu for tour?

A. New York

B. Paris

C. Kashmir

D. None

E. All of the above

Solution

Given Details

Eight persons Sanju, Jay, Athul, Gopu, Aswin, Raghu, Kripa, and Rahul.

The tourist spots are Paris, Kashmir, and New York.

At least two persons went to a tourist spot and at most three persons went to a tourist spot.

Gopu doesn’t go to Kashmir.

Gopu went on tour with Rahul to the same place.

Rahul doesn’t go to Paris.

From these, we get that Gopu and Rahul went to New York.

Tourist Spot	Names of People
Paris
Kashmir
New York	Gopu, Rahul

Sanju went on tour with Raghu only.

More than two people went on tour to Paris.

From these we get, Sanju and Raghu went tour to Kashmir

Tourist Spot	Names of People
Paris
Kashmir	Sanju, Raghu
New York	Gopu, Rahul

Jay went on tour with two other people but not in New York.

Athul and Kripa went on tour together to the same place.

From these, we get that Jay went with Athul and Kripa to Paris while Aswin went to New York.

Final arrangement.

Tourist Spot	Names of People
Paris	Athul, Jay, Kripa
Kashmir	Sanju, Raghu
New York	Gopu, Rahul, Aswin

From the final arrangement we get, Gopu went on tour to New York.

38. To which place did Sanju and Raghu go together?

A. New York

B. Kashmir

C. Paris

D. None of the above

E. All of the above

Solution

Given Details

Eight persons Sanju, Jay, Athul, Gopu, Aswin, Raghu, Kripa, and Rahul.

The tourist spots are Paris, Kashmir, and New York.

At least two persons went to a tourist spot and at most three persons went to a tourist spot.

Gopu doesn’t go to Kashmir.

Gopu went on tour with Rahul to the same place.

Rahul doesn’t go to Paris.

From these, we get that Gopu and Rahul went to New York.

Tourist Spot	Names of People
Paris
Kashmir
New York	Gopu, Rahul

Sanju went on tour with Raghu only.

More than two people went on tour to Paris.

From these we get, Sanju and Raghu went tour to Kashmir

Tourist Spot	Names of People
Paris
Kashmir	Sanju, Raghu
New York	Gopu, Rahul

Jay went on tour with two other people but not in New York.

Athul and Kripa went on tour together to the same place.

From these, we get that Jay went with Athul and Kripa to Paris while Aswin went to New York.

Final arrangement.

Tourist Spot	Names of People
Paris	Athul, Jay, Kripa
Kashmir	Sanju, Raghu
New York	Gopu, Rahul, Aswin

From the final arrangement we get, Sanju went to Kashmir with Raghu.

39. With whom did Rahul go on tour?

A. Raghu

B. Aswin

C. Athul

D. Jay

E. Kripa

Solution

Given Details

Eight persons Sanju, Jay, Athul, Gopu, Aswin, Raghu, Kripa, and Rahul.

The tourist spots are Paris, Kashmir, and New York.

At least two persons went to a tourist spot and at most three persons went to a tourist spot.

Gopu doesn’t go to Kashmir.

Gopu went on tour with Rahul to the same place.

Rahul doesn’t go to Paris.

From these, we get that Gopu and Rahul went to New York.

Tourist Spot	Names of People
Paris
Kashmir
New York	Gopu, Rahul

Sanju went on tour with Raghu only.

More than two people went on tour to Paris.

From these we get, Sanju and Raghu went tour to Kashmir

Tourist Spot	Names of People
Paris
Kashmir	Sanju, Raghu
New York	Gopu, Rahul

Jay went on tour with two other people but not in New York.

Athul and Kripa went on tour together to the same place.

From these, we get that Jay went with Athul and Kripa to Paris while Aswin went to New York.

Final arrangement.

Tourist Spot	Names of People
Paris	Athul, Jay, Kripa
Kashmir	Sanju, Raghu
New York	Gopu, Rahul, Aswin

From the final arrangement we get, Rahul went on tour with Aswin.

40. Who among the following went to Kashmir?

A. Sanju

B. Gopu

C. Aswin

D. Jay

E. Kripa

Solution

Given Details

Eight persons Sanju, Jay, Athul, Gopu, Aswin, Raghu, Kripa, and Rahul.

The tourist spots are Paris, Kashmir, and New York.

At least two persons went to a tourist spot and at most three persons went to a tourist spot.

Gopu doesn’t go to Kashmir.

Gopu went on tour with Rahul to the same place.

Rahul doesn’t go to Paris.

From these, we get that Gopu and Rahul went to New York.

Tourist Spot	Names of People
Paris
Kashmir
New York	Gopu, Rahul

Sanju went on tour with Raghu only.

More than two people went on tour to Paris.

From these we get, Sanju and Raghu went tour to Kashmir

Tourist Spot	Names of People
Paris
Kashmir	Sanju, Raghu
New York	Gopu, Rahul

Jay went on tour with two other people but not in New York.

Athul and Kripa went on tour together to the same place.

From these, we get that Jay went with Athul and Kripa to Paris while Aswin went to New York.

Final arrangement.

Tourist Spot	Names of People
Paris	Athul, Jay, Kripa
Kashmir	Sanju, Raghu
New York	Gopu, Rahul, Aswin

From the final arrangement we get Sanju went to Kashmir.

Numerical Ability

41.In the following number series, the wrong number is given, find out that number.

123, 121, 111, 99, 83, 63

A. 121

B. 111

C. 99

D. 83

E. 123

Solution

The pattern followed by the series is

123 – 4 = 119

119 – 8 = 111

111 – 12 = 99

99 – 16 = 83

83 – 20 = 63

42. In each of the following number series, the wrong number is given, find out that number.

11, 13, 16, 21, 28, 37

A. 21

B. 13

C. 28

D. 37

E. 16

Solution

The series follows the following pattern:

11 + 2 = 13

13 + 3 = 16

16 + 5 = 21

21 + 7 = 28

28 + 11 = 39

∴ The wrong term in the series is 37.

43. In each of the following number series, a wrong number is given. Find out that number.

280, 270, 240, 210, 130, -30

A. 270

B. 240

C. 210

D. 130

E. -30

Solution

The series follows the following pattern

280 – 10 = 270

270 – 20 = 250

250 – 40 = 210

210 – 80 = 130

130 – 160 = – 30

∴ The wrong number in the series is 240

44. In each of the following number series, the wrong number is given, find out that number.

122, 171, 228, 291, 366, 447

A. 228

B. 171

C. 291

D. 447

E. 366

Solution

The series follows the following pattern:

11² + 1 = 122

13² + 2 = 171

15² + 3 = 228

17² + 4 = 293

19² + 5 = 366

21² + 6 = 447

∴ The wrong term in the series is 291.

45. In each of the following number series, the wrong number is given, find out that number.4, 7, 15, 30, 54, 91, 137

A. 54

B. 30

C. 15

D. 7

E. 91

Solution

We can observe the pattern: (Double difference series)

∴ 91 is the wrong term and must be replaced with 89.

There are two areas in Jaipur – Mansarovar and Vaishali Nagar. The total population of Vaishali Nagar is 300 more than the total population of Mansarovar. 40% of total population of Mansarovar is doctors and 60% of total population of Vaishali Nagar is doctors. The ratio of male to female doctors in Mansarovar and Vaishali Nagar is 4 ∶ 5 and 7 ∶ 5 respectively and the total population of Mansarovar is 900.

46. What is the product of average of total male doctors from both areas and the average of female doctors from both area?

A. 85000

B. 82500

C. 70000

D. 72500

E. None of these

Solution

Given that:

Total population of Mansarovar = 900

Total doctors in Mansarovar = 40% of 900 = 360

Ratio of male and female doctors in Mansarovar = 4 ∶ 5

So, the Male doctors in Mansarovar = 360 × 4/9 = 160

Female doctors in Mansarovar = 360 × 5/9 = 200

Now, total population of Vaishali Nagar =(900 + 300) = 1200

Total doctors in Vaishali Nagar = 60% of 1200 = 720

Ratio of male and female doctors in Vaishali Nagar = 7 ∶ 5

So, the Male doctors in Vaishali Nagar = 720 × 7/12 = 420

Female doctors in Vaishali Nagar = 720 × 5/12 = 300

	Number of doctor	Male doctor	Female doctor	Total
Mansarovar	360	160	200	900
Vaishali Nagar	720	420	300	1200

Formula:

Average = sum of total doctors in areas/no. of areas

Calculation:

Average of male doctors = (160 + 420)/2 = 580/2 = 290

Average of Female doctors = (200 + 300)/2 = 250

Required product = 290 × 250 = 72500

∴ Product is 72500.

47. 30% of the number of Male doctors in Mansarovar are what percent of the 120% of the number of female doctors in Vaishali Nagar?

A. 10%

B. 11%

C. 13.33%

D. 16%

E. None of these

Solution

Given that:

Total population of Mansarovar = 900

Total doctors in Mansarovar = 40% of 900 = 360

Ratio of male and female doctors in Mansarovar = 4 ∶ 5

So, the Male doctors in Mansarovar = 360 × 4/9 = 160

Female doctors in Mansarovar = 360 × 5/.9 = 200

Now, total population of Vaishali Nagar =(900 + 300) = 1200

Total doctors in Vaishali Nagar = 60% of 1200 = 720

Ratio of male and female doctors in Vaishali Nagar = 7 ∶ 5

So, the Male doctors in Vaishali Nagar = 720 × 7/12 = 420

Female doctors in Vaishali Nagar = 720 × 5/12 = 300

Number of doctor	Total Doctors	Male doctor	Female Doctors
Mansarovar	360	160	200	900
Vaishali Nagar	720	420	300	1200

According to the question,

30% of the number of Male doctors in Mansarovar =160 × 30/100 = 48

120% of the number of Female doctors in Vaishali Nagar = 300 × 120/100 = 360

Required% = (48/360) × 100

⇒ 13.33%

∴ required percent is 13.33%.

48. Total Male doctors from both areas are how much more or less than total population of Mansarovar?

A. 500

B. 620

C. 400

D. 320

E. None of these

Solution

Given that:

Total population of Mansarovar = 900

Total doctors in Mansarovar = 40% of 900 = 360

Ratio of male and female doctors in Mansarovar = 4 ∶ 5

So, the Male doctors in Mansarovar = 360 × 4/9 = 160

Female doctors in Mansarovar = 360 × 5/.9 = 200

Now, total population of Vaishali Nagar =(900 + 300) = 1200

Total doctors in Vaishali Nagar = 60% of 1200 = 720

Ratio of male and female doctors in Vaishali Nagar = 7 ∶ 5

So, the Male doctors in Vaishali Nagar = 720 × 7/12 = 420

Female doctors in Vaishali Nagar = 720 × 5/12 = 300

	Total doctor	Male doctor	Female doctor
Mansarovar	360	160	200	900
Vaishali Nagar	720	420	300	1200

Formula:

Required difference = (total population of Mansarovar – total Male doctors of both areas)

Calculation:

Male doctors in both areas = 160 + 420 = 580

Population of Mansarovar = 900

Difference = 900 – 580 = 320

∴ Total Male doctors form both areas are 320 less than total population of Mansarovar.

49. What is the ratio of Male doctors from Mansarovar to Female doctors from Vaishali Nagar?

A. 3 : 2

B. 15 : 8

C. 2 : 3

D. 8 : 15

E. None of these

Solution

Given that:

Total population of Mansarovar = 900

Total doctors in Mansarovar = 40% of 900 = 360

Ratio of male and female doctors in Mansarovar = 4 ∶ 5

So, the Male doctors in Mansarovar = 360 × 4/9 = 160

Female doctors in Mansarovar = 360 × 5/.9 = 200

Now, total population of Vaishali Nagar =(900 + 300) = 1200

Total doctors in Vaishali Nagar = 60% of 1200 = 720

Ratio of male and female doctors in Vaishali Nagar = 7 ∶ 5

So, the Male doctors in Vaishali Nagar = 720 × 7/12 = 420

Female doctors in Vaishali Nagar = 720 × 5/12 = 300

Number of doctor	Male doctor	Female doctor	Total
Mansarovar	160	200	360	900
Vaishali Nagar	420	300	720	1200

Formula:

Required ratio = Male doctors of Mansarovar ∶ Female doctors of Vaishali Nagar

Calculation:

Required ratio = 160 ∶ 300

⇒ 8 ∶ 15

∴ The ratio of Male doctors of Mansarovar to Female doctors of Vaishali Nagar is 8 ∶ 15.

50. Total number of Female doctors from both areas is what percent more or less than total population of Vaishali Nagar?

A. 55.33%

B. 56%

C. 58.33%

D. 50%

E. None of these

Solution

Given that:

Total population of Mansarovar = 900

Total doctors in Mansarovar = 40% of 900 = 360

Ratio of male and female doctors in Mansarovar = 4 ∶ 5

So, the Male doctors in Mansarovar = 360 × 4/9 = 160

Female doctors in Mansarovar = 360 × 5/9 = 200

Now, total population of Vaishali Nagar =(900 + 300) = 1200

Total doctors in Vaishali Nagar = 60% of 1200 = 720

Ratio of male and female doctors in Vaishali Nagar = 7 ∶ 5

So, the Male doctors in Vaishali Nagar = 720 × 7/12 = 420

Female doctors in Vaishali Nagar = 720 × 5/12 = 300

Number of doctor	Total doctor	Male doctor	Female Doctor
Mansarovar	360	160	200	900
Vaishali Nagar	720	420	300	1200

Formula:

Required% = [(difference of total Female doctors of of both areas and total population of Vaishali Nagar)/total population of Vaishali Nagar ] × 100

Calculation:

Total Female doctors of both areas = 200 + 300 = 500

Total population of Vaishali Nagar = 1200

Required% = [(1200 – 500)/1200]× 100

⇒ 700/12 = 58.33%

∴ the required answer is 58.33%

51. In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. x² + x – 6 = 0

II. y² – 11y + 18 = 0

A. x > y

B. x < y

C. x ≥ y

D. x ≤ y

E. x = y or relationship between x and y cannot be established.

Solution

I. x² + x – 6 = 0

⇒ x² + 3x – 2x – 6 = 0

⇒ x(x + 3) – 2(x + 3) = 0

⇒ (x + 3) (x – 2) = 0

⇒ x = –3, 2

II. y² – 11y + 18 = 0

⇒ y² – 2y – 9y + 18 = 0

⇒ y(y – 2) – 9(y – 2) = 0

⇒ (y – 2) (y – 9) = 0

⇒ y = 2, 9

Value of x	Value of y	Relation
–3	2	x < y
–3	9	x < y
2	2	x = y
2	9	x < y

∴ x ≤ y

52. In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. 8x² + 10x + 3 = 0

II. 2y² + 17y + 21 = 0

A. x > y

B. x < y

C. x ≥ y

D. x ≤ y

E. x = y or relationship between x and y cannot be established.

Solution

I. 8x² + 10x + 3 = 0

⇒ 8x² + 6x + 4x + 3 = 0

⇒ (2x + 1) (4x + 3) = 0

⇒ x = -1/2, -3/4

II. 2y² + 17y + 21 = 0

⇒ 2y² + 14y + 3y + 21= 0

⇒ (2y + 3) (y + 7) = 0

⇒ y = -3/2, -7

Value of x	Value of y	Relation
-1/2	-3/2	x > y
-1/2	-7	x > y
-3/4	-3/2	x > y
-3/4	-7	x > y

∴ x > y.

53. In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. x² + 11x + 28 = 0

II. y² + 10y + 21 = 0

A. x > y

B. x < y

C. x ≥ y

D. x ≤ y

E. x = y or relationship between x and y cannot be established.

Solution

Calculations:

I. x² + 11x + 28 = 0

⇒ x² + 7x + 4x + 28 = 0

⇒ x(x + 7) + 4(x + 7) = 0

⇒ (x + 4) (x + 7) = 0

⇒ x = –4, –7

II. y² + 10y + 21 = 0

⇒ y2 + 7y + 3y + 21 = 0

⇒ y(y + 7) + 3(y + 7) = 0

⇒ (y + 7) (y + 3) = 0

⇒ y = –3, –7

Comparison between x and y (via Tabulation):

Value of x	Value of y	Relation
–4	–3	x < y
–4	–7	x > y
–7	–3	x < y
–7	–7	x = y

Comparison between x and y (via Line graph):

∴ x = y or the relationship between x and y cannot be established.

54. In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. x2 + 18x + 72 = 0

II. y² + 12y + 36 = 0

A. x > y

B. x < y

C. x ≥ y

D. x ≤ y

E. x = y or the relationship between x and y cannot be established.

Solution

I. x2 + 18x + 72 = 0

⇒ x2 + 6x + 12x + 72 = 0

⇒ x(x + 6) + 12 (x + 6) = 0

⇒ (x + 6) (x + 12) = 0

⇒ x = – 6, – 12

II. y2 + 12y + 36 = 0

⇒ y2 + 6y + 6y + 36 = 0

⇒ y (y + 6) + 6 (y + 6) = 0

⇒ (y + 6) (y + 6) = 0

⇒ y = – 6, – 6

Comparison between x and y (via Tabulation):

Value of x	Value of y	Relation
-6	-6	x = y
-6	-6	x = y
-12	-6	x < y
-12	-6	x < y

Comparison between x and y (via Line graph):

Hence, x ≤ y

55. In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. x² – 13x + 30 = 0

II. y²+ 5y + 4 = 0

A. x > y

B. x < y

C. x ≥ y

D. x ≤ y

E. x = y or relationship between x and y cannot be established.

Solution

I. x² – 13x + 30 = 0

⇒ x² – 3x – 10x + 30 = 0

⇒ (x – 3) (x – 10) = 0

⇒ x = 3, 10

II. y²+ 5y + 4 = 0

⇒ y²+ y + 4y + 4 = 0

⇒ (y + 4) (y + 1) = 0

⇒ y = –4, –1

Value of x	Value of y	Relation
3	–4	x > y
3	–1	x > y
10	–4	x > y
10	–1	x > y

Hence, x > y.

Shortcut Trick

When two equations are in the form as below

a₁x² – b₁x + c₁ = 0

a₂y² + b₂y + c₂ = 0

Answer will be always x > y.

56. There are two positive numbers in the ratio 2 : 7. If the larger number exceeds the smaller number by 15, then find the smaller number.

A. 5

B. 4

C. 6

D. 7

E. 3

Solution

Given:

The difference between the numbers is 15

The ratio of two numbers is 2 : 7

Calculation:

Let the numbers be 2x and 7x

According to the question,

7x – 2x = 15

⇒ 5x = 15

⇒ x = 3

⇒ Smaller number = 2x = 2 × 3 = 6

∴ The smaller number is 6.

57. In what ratio must milk costing Rs. 6.50 per litre be mixed with water costing Rs. 14 per litre, so that the mixture be worth Rs. 12 per litre?

A. 4 : 7

B. 7 : 4

C. 4 : 11

D. 11 : 4

E. 1 : 1

Solution

Given:

The cost of milk per litre = Rs. 6.50

The cost of water per litre = Rs. 14

The cost of mixture per litre = Rs. 12

Concept:

Alligation method,

The required ratio = (Y – M) : (M – X)

Calculation:

By alligation method,

Required ratio = 2 : 5.50

⇒ 2 : (11/2)

⇒ 4 : 11

∴ The required ratio will be 4 : 11.

58. A boat travels 88 kms downstream and 65 km upstream in 9 hours while it travels 121 km downstream and 97.5 km upstream in 13 hours. Find the speed of stream(in km/hr).

A. 1.5

B. 2.5

C. 3.5

D. 4.5

E. 5.5

Solution

Given:-

Time for 88 kms downstream and 65 km upstream = 9 hours

Time for 121 kms downstream and 97.5 km upstream = 13 hours

Formula:-

Speed = Distance/Time

Downstream speed = u + v

Upstream speed = u – v

Boat speed = ½ (D + U)

Stream speed = ½ (D – U)

U and v are boat and stream speeds and D and U downstream and upstream speeds.

Calculation:-

88/(u + v) + 65/(u – v) = 9

121/(u + v) + 97.5/(u – v) = 13

Let 1/(u + v) = x and 1/(u – v) = y

88x + 65y = 9

121x + 97.5y = 13

Solving both, x = 1/22 and y = 1/13

Or U = 13 and D = 22

V = ½ (22 – 13) = 4.5 km/hr

59. The area of a square is 441 sq cm and its side is half of the radius of a circle. Find the circumference of the circle.

A. 264 cm

B. 484 cm

C. 286 cm

D. 584 cm

E. 224 cm

Solution

Given:

Area of a square = 441 sq cm

Side of the square = (1/2) of the radius of the circle

Formula used:

Area of a square = (Side)²

Circumference of a circle = 2πr

Calculation:

Let a be the side of a square.

441 = (a)²

⇒ a = 21

Radius of the circle = 2 × 21 = 42

⇒ Circumference of the circle = 2 × (22/7) × 42

⇒ Circumference of the circle = 264

∴ The circumference of the circle is 264 cm.

60. A can finish a work in 6 days. B can finish a work in 10 days. What is the ratio of the amounts that A and B would be paid for the same amount of work if they finish it individually.

A. 3 : 4

B. 4 : 5

C. 5 : 3

D. 2 : 1

E. 3 : 2

Solution

Ratio of A and B one day’s work = 1/6 : 1/10 = 5 : 3.Hence, ratio of amounts they will be paid for the same amount of work = 5 : 3.

61. What will come in the place of the question mark ? in the following question ?

12% of 220 – 11% of 240 + 46² = ?²

A. 56

B. 66

C. 34

D. 46

E. 52

Solution

Solution :

Concept used :

Follow the BODMAS rule to solve this question, as per the question is given below:

Step 1: Parts of an equation enclosed in ‘ Brackets ‘ must be solved first and in the bracket,

Step 2: Any mathematical ‘ of ‘ or ‘exponent’ must be solved next,

Step 3: Next, The part of the equation that contains ‘Division’ and ‘multiplication’ are calculated,

Step 4: Last but not least, the parts of the equation that contains ‘Addition ‘ and ‘Subtraction’ should be calculated

Given :

⇒ 12% of 220 – 11% of 240 + 46² = ?²

⇒ 12 × 220 / 100 – 11 × 240 / 100 + 46² = ?²

⇒ 1.2 × 22 – 11 × 2.4 + 46² = ?²

⇒ 26.4 – 26.4 + 46² = ?²

⇒ 46² = ?²

⇒ ? = 46

Hence 46 is the correct answer.

62. Fill in the question mark (?) in the equation:

? = 18% of 850 + 22% of 700

A. 307

B. 317

C. 327

D. 337

E. 347

Solution

Concept Used:

Apply the BODMAS rule.

Calculation:

? = 18% of 850 + 22% of 700

? = (18/100) × 850 + (22/100) × 700

? = 153 + 154

∴ ? = 307

63. What will come in the place of the question mark ‘?’ in the following question?

125 × 20% – 130 × 30% + ? = 515 + 52

A. 382

B. 581

C. 591

D. 335

E. 585

Solution

Given:

125 × 20% – 130 × 30% + ? = 515 + 52

Concept used:

Follow the ‘BODMAS’ Rule

B ⇒ Bracket, O ⇒ of, D ⇒ Division, M ⇒ Multiplication, A ⇒ Add, S ⇒ Subtraction

Calculation:

⇒ 125 × 20% – 130 × 30% + ? = 515 + 52

⇒ 25 – 39 + ? = 567

⇒ -14 + ? = 567

⇒ ? = 581

∴ The value of ? is 581.

64. What will come in place of the question mark (?) in the following question?

15² – 45 × 2 + 8 × 4 = ?

A. 125

B. 167

C. 143

D. 165

E. 109

Solution

Concept Used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

152 – 45 × 2 + 8 × 4 = ?

⇒ 225 – 90 + 32 = ?

⇒ 257 – 90 = ?

⇒ 167 = ?

∴ The correct answer is 167.

65. What will come in place of the question mark (?) in the following question?

(3/5×125)÷(9/3)+12=?

A. 48

B. 37

C. 53

D. 26

E. 62

Solution

Concept Used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

(35×125)÷(93)+12=?(35×125)÷(93)+12=?

75 ÷ 3 + 12 = ?

25 + 12 = ?

∴ 37 will come in place of the question mark

66. What will come in place of the question mark (?) in the following question?

96 ÷ 8 × 6 – 14 + 72 ÷ 9 = ?

A. 45

B. 32

C. 66

D. 57

E. 78

Solution

Concept Used:

Follow BODMAS rule to solve this question, as per the order given below,

Calculation:

96 ÷ 8 × 6 – 14 + 72 ÷ 9 = ?

12 × 6 – 14 + 8 = ?

72 – 14 + 8 = ?

58 + 8 = ?

∴ 66 will come in place of the question mark

67. What will come in the place of the question mark ‘?’ in the following question?

40% of 75 + 32% of 350 + 36 ÷ 18 = ?

A. 244

B. 104

C. 204

D. 144

E. 124

Solution

Given:

40% of 75 + 32% of 350 + 36 ÷ 18 = ?

Concept used:

Follow the BODMAS rule according to the given table below:

Calculation:

40% of 75 + 32% of 350 + 36 ÷ 18 = ?

⇒ (40/100) × 75 + (32/100) × 350 + 2 = ?

⇒ (2/5) × 75 + (8/25) × 350 + 2 = ?

⇒ 30 + 112 + 2 = ?

⇒ ? = 144

∴ 144 should come in place of the question mark (?).

68. A transistor was sold at a profit of 20%. If it would have been sold for Rs. 80 less, the profit would have been 15%. What was the cost price of the transistor?

A. Rs. 1,360

B. Rs. 1,600

C. Rs. 1,840

D. Rs. 1,920

E. Rs. 2,000

Solution

Calculation:

Let the cost price be x

1st condition,

S.P. = C.P. × 120% = 1.2x

2nd condition,

S.P. = C.P. × 115% = 1.15x

According to the condition,

⇒ 1.2x – 1.15x = 80

⇒ 0.05x = 80

⇒ x = 80/0.05

⇒ x = 8000/5

∴ x = Rs. 1600

69. If a sum of money yields Rs. 900 as simple interest at 10% p.a. after 3 years. Then, the same sum of money will yield how much compound interest at 20% p.a. in the same time?

A. Rs. 1956

B. Rs. 1834

C. Rs. 2184

D. Rs. 1856

E. Rs. 2298

Solution

Given:

SI = Rs. 900, rate = 10%, time = 3 years

For CI, rate = 20%, time = 3 years

Formula:

SI = P × R × T/100
CI = P[(1 + R/100)ⁿ– 1]

Calculation:

Let the principal be P

900 = 3 × 10 × P/100
⇒ P = Rs. 3000
Now, compound interest after 3 years will be,

∴ CI = 3000[(1 + 20/100)³ – 1]

= 3000 × (91/125) = Rs. 2184

70. Average of x numbers is y³ and the average of y numbers is x³. So find the average of all the numbers taken together ?

Solution

Given:

Average of x numbers is y3

the average of y numbers is x³

Formula used:

Average = Total Sum/Number Of Terms

Calculation:

Total sum of x numbers = x × y³

= xy³

Total sum of y numbers = y × x³

= yx³

Average of all the numbers =

Answer is

Direction: Study the table carefully and answer the following questions.

The following table shows the total number of candidates who qualified for SBI PO in 6 different years and the ratio of boys to girls in them.

Year	Total Qualified Candidates	The ratio of boys to girls
2014	1500	3 : 2
2015	1800	7 : 2
2016	2200	5 : 6
2017	2600	8 : 5
2018	3000	8 : 7
2019	3200	5 : 3

71. What is the ratio of the total number of girls to the total number of boys who qualified for the SBI PO exam in the years 2015, 2017 and 2019 together?

A. 12 : 25

B. 13 : 25

C. 25 : 13

D. 25 : 12

E. 11 : 25

Solution

Given:

Year	Total Qualified Candidates	The ratio of boys to girls
2015	1800	7 : 2
2017	2600	8 : 5
2019	3200	5 : 3

Calculation:

The number of girls who qualified for the SBI PO exam in the year 2015 = {2/(2 + 7)} × 1800

⇒ (2/9) × 1800

⇒ 400

The number of boys who qualified for the SBI PO exam in the year 2015 = 1800 – 400

⇒ 1400

Similarly,

Year	Number of girls	Number of boys
2015	(2/9) × 1800 = 400	1800 – 400 = 1400
2017	(5/13) × 2600 = 1000	2600 – 1000 = 1600
2019	(3/8) × 3200 = 1200	3200 – 1200 = 2000

The total number of girls who qualified for the SBI PO exam in the years 2015, 2017 and 2019 together = 400 + 1000 + 1200

⇒ 2600

The total number of boys who qualified for the SBI PO exam in the years 2015, 2017 and 2019 together = 1400 + 1600 + 2000

⇒ 5000

The required ratio = 2600/5000

⇒ 13 : 25

∴ The ratio of the total number of girls to the total number of boys who qualified for the SBI PO exam in the years 2015, 2017 and 2019 together will be 13 : 25.

Direction: Study the table carefully and answer the following questions.

The following table shows the total number of candidates who qualified for SBI PO in 6 different years and the ratio of boys to girls in them.

Year	Total Qualified Candidates	The ratio of boys to girls
2014	1500	3 : 2
2015	1800	7 : 2
2016	2200	5 : 6
2017	2600	8 : 5
2018	3000	8 : 7
2019	3200	5 : 3

72. The number of boy candidates who qualified in the Year 2015 approximately what percent of the total number of candidates who qualified for the exam in the year 2016?

A. 50%

B. 63.64%

C. 68%

D. 73.74%

E. 70%

Solution

Given:

Year	Total Qualified Candidates	The ratio of boys to girls
2015	1800	7 : 2
2016	2200	5 : 6

Calculation:

The number of boy candidates who qualified in the year 2015 = {7/(2 + 7)} × 1800

⇒ (7/9) × 1800

⇒ 1400

The total number of candidates who qualified for the exam in the year 2016 = 2200

The required percentage = (1400/2200) × 100

⇒ 700/11

⇒ 63.64%

∴ The number of boy candidates who qualified in the Year 2015 will be approximately 63.64% of the total number of candidates who qualified for the exam in the year 2016.

Direction: Study the table carefully and answer the following questions.

The following table shows the total number of candidates who qualified for SBI PO in 6 different years and the ratio of boys to girls in them.

Year	Total Qualified Candidates	The ratio of boys to girls
2014	1500	3 : 2
2015	1800	7 : 2
2016	2200	5 : 6
2017	2600	8 : 5
2018	3000	8 : 7
2019	3200	5 : 3

73. What is the average number of girl candidates who qualified for the exam in the Year 2014, 2015 and 2018 together?

A. 700

B. 800

C. 900

D. 880

E. 780

Solution

Given:

Year	Total Qualified Candidates	The ratio of boys to girls
2014	1500	3 : 2
2015	1800	7 : 2
2018	3000	8 : 7

Formula Used:

Average = (Sum of all observations)/(Number of observations)

Calculation:

The number of girl candidates who qualified for the exam in 2014 = {2/(2 + 3)} × 1500

⇒ (2/5) × 1500

⇒ 600

The number of girl candidates who qualified for the exam in 2015 = {2/(2 + 7)} × 1800

⇒ (2/9) × 1800

⇒ 400

The number of girl candidates who qualified for the exam in 2018 = {7/(7 + 8)} × 3000

⇒ (7/15) × 3000

⇒ 1400

Total number of girl candidates who qualified for the exam in the Year 2014, 2015 and 2018 together = 600 + 400 + 1400

⇒ 2400

The required average = 2400/3

⇒ 800

∴ The average number of girl candidates who qualified for the exam in the Year 2014, 2015 and 2018 together will be 800.

Direction: Study the table carefully and answer the following questions.

The following table shows the total number of candidates who qualified for SBI PO in 6 different years and the ratio of boys to girls in them.

Year	Total Qualified Candidates	The ratio of boys to girls
2014	1500	3 : 2
2015	1800	7 : 2
2016	2200	5 : 6
2017	2600	8 : 5
2018	3000	8 : 7
2019	3200	5 : 3

74. What is the difference between the number of boy candidates qualified in the year 2015 and 2019 together and the number of girl candidates who qualified in the year 2016 and 2017 together?

A. 1000

B. 1100

C. 800

D. 2200

E. 1200

Solution

Given:

Year	Total Qualified Candidates	The ratio of boys to girls
2015	1800	7 : 2
2016	2200	5 : 6
2017	2600	8 : 5
2019	3200	5 : 3

Calculation:

The number of boys who qualified for the SBI PO exam in the year 2015 = {7/(2 + 7)} × 1800

⇒ (7/9) × 1800

⇒ 1400

Similarly,

Year	Number of Boys	Number of Girls
2015	(7/9) × 1800 = 1400
2016		(6/11) × 2200 = 1200
2017		(5/13) × 2600 = 1000
2019	(5/8) × 3200 = 2000

Total number of boy candidates qualified in the year 2015 and 2019 together = 1400 + 2000

⇒ 3400

Total number of girl candidates qualified in the year 2016 and 2017 together = 1200 + 1000

⇒ 2200

The required difference = 3400 – 2200

⇒ 1200

∴ The difference between the number of boy candidates qualified in the year 2015 and 2019 together and the number of girl candidates who qualified in the year 2016 and 2017 together will be 1200.

Direction: Study the table carefully and answer the following questions.

The following table shows the total number of candidates who qualified for SBI PO in 6 different years and the ratio of boys to girls in them.

Year	Total Qualified Candidates	The ratio of boys to girls
2014	1500	3 : 2
2015	1800	7 : 2
2016	2200	5 : 6
2017	2600	8 : 5
2018	3000	8 : 7
2019	3200	5 : 3

75. The number of boys candidates who qualified for the exam in 2018 approximately what percent more or less than the number of girls candidates who qualified for the exam in the year 2019?

A. 33.33% more

B. 30% less

C. 25% more

D. 33.33% less

E. 20% more

Solution

Given:

Year	Total Qualified Candidates	The ratio of boys to girls
2018	3000	8 : 7
2019	3200	5 : 3

Formula Used:

Increase in percentage = {(Increase in value)/(Base value)} × 100

Calculation:

The number of boys candidates who qualified for the exam in 2018 = {8/(8 + 7)} × 3000

⇒ (8/15) × 3000

⇒ 1600

The number of girls candidates who qualified for the exam in 2019 = {3/(3 + 5)} × 3200

⇒ (3/8) × 3200

⇒ 1200

Increase in value = 1600 – 1200

⇒ 400

The required Increased percentage = (400/1200) × 100

⇒ 100/3

⇒ 33.33%

∴ The number of boys candidates who qualified for the exam in 2018 will be approximately 33.33% more than the number of girls candidates who qualified for the exam in the year 2019.

76. The ratio of the present ages of a girl and her grandmother is 1 : 3. Ten years ago, the age of grandmother was 4 more than 4 times the age of a girl. Find their ages?

A. 22 and 72

B. 26 and 78

C. 25 and 78

D. 26 and 77

E. 23 and 79

Solution

Given:

The ratio of the present ages of a girl and her grandmother is 1 : 3. Ten years ago, age of grandmother is 4 more than 4 times the age of a girl

Calculation:

Let the ages be x and 3x

Ten years ago

Girl’s age = x – 10 and Grandmother’s age = 3x – 10

According to question,

⇒ 3x – 10 = 4(x – 10) + 4

⇒ 3x – 10 = 4x – 40 + 4

⇒ x = 26

3x = 3 × 26 = 78

∴ Age of girl is 26 years and age of grandmother is 78 years.

77. A man reaches his office 30 min late, if he travel from his home at 30 km per hour and reaches 40 min early if he travel 40 km per hour. How far is his office from his home?

A. 120 km

B. 125 km

C. 130 km

D. 140 km

E. None of these

Solution

Given:

When man’s speed 30 kmph, he reaches his office 30 min late

And man’s speed 40 kmph, he reaches his office 40 min early

Formula used:

Time = dist./speed

Calculation:

Let the Distance between home and office = d

Suppose he reaches the office on time, the Time taken = x minutes

Case 1:

When he reaches office 30 minutes late

So, Time taken = x + 30

⇒ x+30 = d/30 …….(1)

Case 2:

When he reaches office 40 minutes early

So, Time taken = x – 40

⇒ x – 40 = d/40 …….(2)

Equation (1) – Equation (2)

⇒ 70 min = d/30 – d/40

⇒ 70/60 h = d/120

⇒ d = 140 km

∴ Distance between home and office is 140 km

Alternate Method

Given:

When man’s speed 30 kmph, he reaches his office 30 min late

And man’s speed 40 kmph, he reaches his office 40 min early

Formula used:

Distance = (S₁xS₂)/(S₂-S₁){diff. b/w time}

Calculation:

Difference between time = 30-(-40) = 70 min = 70/60 h

⇒ D = (30×40)/(40-30){70/60}

⇒ D = 140 km

∴ Distance between home and office is 140 km

78. A start a business with Rs. 12000, After 4 months B joined with Rs. 16000. Total profit after one year is Rs. 34000. Find the share of profit of A?

A. Rs. 19500

B. Rs. 20500

C. Rs. 18000

D. Rs. 16000

E. Rs. 21000

Solution

Calculation

A: Rs. 12000 for 12 months = 12000 × 12 = 144000
B: Rs. 16000 for 8 months = 16000 × 8 = 128000

Ratio of profit = 144000:128000 = 9:8
Total profit = 34000
A’s share = (9/17) × 34000 = Rs. 18000

79. A trader sells 40 meters of cloth for Rs. 8200 at a profit of Rs. 25 per metre of cloth. How much profit will the trader earn on 40 metres of cloth?

A. Rs. 950

B. Rs. 1500

C. Rs. 1000

D. Rs. 1200

E. None of these

Solution

Given:

40 meters of cloth, SP = Rs. 8200

Profit = Rs. 25 per metre of cloth

Calculation:

S.P. per metre = 8200/40 = Rs. 205

∴ C.P. per metre = RS. (205 – 25) = Rs. 180

∴ C.P. of 40 metre cloth

= Rs. (40 × 180) = Rs. 7200

∴ Gain = Rs. (8200 – 7200) = Rs. 1000

∴ Gain is Rs 1000

80. If the volume of a cylinder is 100π unit and the ratio of radius to height is 5 : 4 then find the curved surface area of the cylinder ?

A. 400π sq. unit

B. 40 sq. unit

C. 40π sq. unit

D. 140π sq. unit

E. None of these

Solution

GIVEN:

Volume of cylinder = 100π

⇒ Radius : Height = 5x : 4x

FORMULA USED:

Volume of cylinder = πr²h cu. Unit

CALCULATION:

⇒ πr²h = 100π unit

⇒ r²h = 100 unit

⇒ 25x² X 4x = 100 unit

⇒ x³ = 1 unit

⇒ Radius = 5 unit & height = 4 unit.

⇒ Curved surface = 2πrh

⇒ Curved surface = 40π sq. unit

IBPS RRB Clerk Prelims Full Test 9

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