1.Match List – I with List-II and select the correct answer using the codes given below the lists:
| List – I(Congress Presidents) | List – II(Venues of Session) |
| (A) Dr M.A. Ansari | 1. Haripura |
| (B) Purshottam Tandon | 2. Kanpur |
| (C) Sarojini Naidu | 3. Madras |
| (D) Subhas Chandra Bose | 4. Nasik |
A. (A) – (1), (B) – (2), (C) – (4), (D) – (3)
B. (A) – (2), (B) – (3), (C) – (1), (D) – (4)
C. (A) – (3), (B) – (4), (C) – (2), (D) – (1)
D. (A) – (4), (B) – (1), (C) – (3), (D) – (2)
Solutions
The correct answer is (A) – (3), (B) – (4), (C) – (2), (D) – (1).
| List – I(Congress Presidents) | List – II(Venues of Session |
| (A) Dr M.A. Ansari | Madras |
| (B) Purshottam Tandon | Nasik |
| (C) Sarojini Naidu | Kanpur |
| (D) Subhas Chandra Bose | Haripura |
2. The volume of a small ball is calculated to be 25 cm3 and it weighs 30 g in air. Will this ball float or sink in water?
A. Sink
B. Partially sink
C. Float
D. Can not be predicted from the given information
Solutions
The Correct answer is Sink.
weighs = 30 g, volume = 25 cm3
We know that the density of the object is given as,
p = m/v
The density of the ball = 30 g / 25 cm3 = 1.2
Compare this density to the density of water. The density of water is approximately 1 g/cm3.
3. Which of the following countries border the Black Sea?
1. Ukraine
2. Russia
3. Romania
4. Serbia
5. Turkey
Select the correct answer using the codes given below.
A. 1 and 2 only
B. 1, 4 and 5 only
C. 2, 3, 4 and 5 only
D. 1, 2, 3 and 5 only
Solutions
The correct answer is 1, 2, 3 and 5 only .
4. The rear side of a truck is open, and a box of 40 kg mass is placed 5 m away from the open end as shown in Fig. On a straight road, the truck starts from rest and accelerates with 2 ms-2. At a distance 20 m from the starting point the box falls off the truck. Find the coefficient of friction between the box and the surface below it
A. 0.15
B. 0.20
C. 0.10
D. 0.25
Solutions
Given, m = 40 kg, distance travelled by the truck, s = 20 m, acceleration of the truck a’ = 2 m/s2
Now net force acting on the box is force due to acceleration of the truck and the maximum kinetic friction.
Let the net acceleration of the box is a, and time after which box is fall is t’.
And distance travelled by box on the truck before fall is s’ = 5 m, initial speed of the box, u = 0 m/s
Then,
⇒ s’ = ut + 1/2at2
⇒ 5 = 0 × t + 1/2 a × t2 — (1)
Also, at same time truck traveled 20 m, with initial speed zero.
Then,
⇒ 20 = 0 × t + 1/2(2) × t2 — (2)
Dividing equation 1 by 2 then,
⇒ a = 0.5 m/s2
Now net force acting on the box is, force due to acceleration of the truck and the maximum kinetic friction.
⇒Fn = ma’ – μmg (-ve due to force due to acceleration and the kinetic friction acting in opposite direction)
⇒ ma = ma’ – μmg
⇒ 0.5 = 2 – μ × 10
⇒ μ = 0.15
5. If the surface areas of three faces of a cuboid sharing a vertex are given as 25 m2, 32 m2 and 32 m2, then what will be the volume of the cuboid?
A. 240 m3
B. 160 m3
C.80 m3
D. 135 m3
Solutions
Trick
Volume(V) = abc = √(25 × 32 × 32)
V = abc = 160 m3
6. Select the appropriate option for the generation of computer and the language used in it.
| A | B | ||
| (1) | first generation | a) | Assembly Language |
| (2) | Second generation | b) | Higher Level Language |
| (3) | Third generation | c) | Machine language |
| (4) | Fourth generation | d) | Structured Query Language |
A. 1-c, 2-a, 3-b, 4-d
B. 1-b, 2-d, 3-a, 4-c
C. 1-b, 2-c, 3-d, 4-a
D. 1-c, 2-a, 3-d, 4-b
Solutions
The correct answer is : 1) 1-c, 2-a, 3-b, 4-d.
| A | B | ||
| (1) | first generation | c) | Machine language |
| (2) | Second generation | a) | Assembly Language |
| (3) | Third generation | b) | Higher Level Language |
| (4) | Fourth generation | d) | Structured Query Language |
7. Mohan divides 14817 by a certain number. If the quotient and the remainder he gets are 98 and 117, respectively, then the divisor is:
A. 150
B. 145
C. 155
D. 140
Solutions
We can substitute the given values into the division formula:
14817 = Divisor × 98 + 117
Our goal is to isolate the Divisor on one side of the equation. First, we need to remove the Remainder from the right side. We can do this by subtracting the Remainder from the Dividend on the left side:
14817 − 117 = Divisor × 98
Let’s perform the subtraction:
14699
14817 − 117 = 14700
So, the equation becomes:
14700 = Divisor × 98
Now, to find the Divisor, we need to divide the result (14700) by the Quotient (98):
Divisor = 14700/98
= 150
8. Which of the following is correct for ammeter?
A. It has low internal resistance in series.
B. It has low resistance in parallel.
C. It has high internal resistance in series.
D. It has high resistance in parallel.
Solutions
The device which is used to measure the current in milliamperes is known as a milliammeter, and the device for measuring extremely small electric currents, calibrated in microamperes is called a microammeter. In a circuit, the ammeter is represented by the letter “A”.
Ammeter, instrument for measuring either direct (DC) or alternating (AC) electric current, in amperes.
An ammeter can measure a wide range of current values because at high values only a small portion of the current is directed through the meter mechanism; a shunt in parallel with the meter carries the major portion.
Ideally, an ammeter should have very low internal resistance.
This minimizes the change in circuit behavior due to the insertion of the ammeter.
If the ammeter had significant resistance, it could reduce the current flowing in the circuit, affecting the measurement and the circuit’s performance.
To measure the current, generally, the ammeter is connected in series with the circuit.
This device is mainly used for measuring a small amount of current, and the current is measured in the milliampere or microampere range.
9. If A = The set of lines which are parallel to the x – axis and B = The set of numbers which are multiples of 5 ?
A. A is a finite set but B is an infinite set
B. A is an infinite set but B is a finite set
C. Both A and B are infinite sets
D. Both A and B are finite sets
Solutions
Given: A = The set of lines which are parallel to the x – axis and B = The set of numbers which are multiples of 5
As we know that, we can draw infinite number of lines parallel to the x – axis
So, A is an infinite set
Similarly, B = {5n : n ∈ Z}
We can see that, B is also infinite set
Hence, option 3 is the correct answer.
10. Semiconductors (e.g. germanium, silicon etc.) are those substances whose electrical conductivity lies in between conductors and insulators. In terms of energy band, the valence band is _______ and conduction band is ________
A. almost filled, almost empty
B. almost empty, almost filled
C. almost filled, almost filled
D. almost empty, almost empty
Solutions
Forbidden energy gap (ΔEg): The energy gap between the conduction band and valence band is known as the forbidden energy gap i.e.,
ΔEg = (C.B)min – (V.B)ma
As temperature increases, the forbidden energy gap decreases very slightly.
No free electron is present in the forbidden energy gap.
The width of the forbidden energy gap depends upon the nature of the substance.
11. Which country has significant deposits of uranium and thorium used for nuclear power?
A. USA
B. Russia
C. India
D. China
Solutions
The correct answer is ‘India‘
The Indian nuclear power program is focused on utilizing these resources, with a particular emphasis on exploiting thorium due to its abundance and potential for long-term energy security.
India’s Uranium and Thorium Deposits:
India has significant deposits of uranium and thorium, which are crucial for the country’s nuclear power program.
Large reserves of thorium are found along the coastal regions, particularly in the state of Kerala. India has one of the largest thorium reserves in the world.
Uranium deposits are found in several regions across the country, including Jharkhand, Andhra Pradesh, and Rajasthan.
12. Which is NOT a peripheral device ?
A. Visual display unit
B. Main Memory chip
C. Modem
D. Pen Drive
Solutions
The correct answer is Main Memory chip.
They are considered part of the central processing unit (CPU) and are not considered peripheral devices.
Main Memory chips are internal components of a computer that store data and instructions for the CPU to process.
13. Select the correct alternative to indicate the sequential order of the following terms in a meaningful manner.
1. Heart
2. Pelvis
3. Cornea
4. Kidney
5. Pinna
A. 3 – 5 – 1 – 4 – 2
B. 3 – 5 – 4 – 1 – 2
C. 2 – 1 – 4 – 3 – 5
D. 5 – 3 – 1 – 4 – 2
Solutions
Considering the head-to-toe sequence, we expect parts from the head first, then chest, then abdomen, then lower torso. Let’s look at the indices from the question:
- Cornea: 3 (Head)
- Pinna: 5 (Head)
- Heart: 1 (Chest)
- Kidney: 4 (Abdomen)
- Pelvis: 2 (Lower Torso)
A head-to-toe order would therefore place 3 and 5 before 1, 1 before 4, and 4 before 2. The exact order of 3 and 5 needs to fit one of the options.
Let’s examine the sequence implied by the correct option:
The sequence 3 – 5 – 1 – 4 – 2 corresponds to:
14. Select the option that is similar to the keyword given:
Ghumar
A. Kathak
B. Odissi
C. Kathakali
D. Garba
Solutions
Ghumar → Folk dance of Rajasthan.
Similarly:
Garba → Folk dance of Gujrat.
Here, Garba is similar to the Ghumar.
Hence, the correct answer is “Garba”.
15. What is the decimal equivalent number of binary number 101101?
A. 45
B. 90
C. 40
D. 8
Solutions
To convert the binary number 101101 to decimal, follow these two steps:
Here is the final answer, The binary number 1011012 converted to decimal is therefore equal 4510
Start from one’s place in 101101: multiply one place with 2^0, tens place with 2^1, hundreds place with 2^2 and so on from right to left
Add all the products we got from step 1 to get the decimal equivalent of 101101. Using the above steps, here is the work involved in the solution for converting 101101 to a decimal number (Don’t forget that we start from one place to so on…)
Decimal equivalent of “1” = 1 × 2^0 = 1
Decimal equivalent of “0” = 0 × 2^1 = 0
Decimal equivalent of “1” = 1 × 2^2 = 4
Decimal equivalent of “1” = 1 × 2^3 = 8
Decimal equivalent of “0” = 0 × 2^4 = 0
Decimal equivalent of “1” = 1 × 2^5 = 32
The decimal equivalent of “101101” = 45
16. Which term from among the given options can replace the question mark (?) in the following series to make it logically complete?
BV 101, ? DX 109, EY 113, FZ 117
A. CW 105
B. CV 104
C. CW 106
D. CV 107
Solution
The logic followed here is as follows
Hence, ‘CW 105‘ will come in place of the question mark in the given series.
17. _______ are equations that perform calculations on values in your Excel Worksheet.
A. Functions
B. References
C. Formulas
D. Constants
Solutions
The correct answer is Formulas.
Formulas can range from simple arithmetic operations to complex calculations involving nested functions.
Formulas in Excel are equations that perform calculations on values in your Excel worksheet.
They can combine values, cell references, operators, and functions to produce a new value.
Formulas are used to perform operations such as addition, multiplication, and comparison across cells.
For example, the formula =A1+A2 adds the values in cells A1 and A2.
18. Which type of transistor is commonly used in preamplifier circuits due to its high input impedance and low output impedance characteristics?
A. Bipolar Junction Transistor (BJT)
B. Field Effect Transistor (FET)
C. Metal-Oxide-Semiconductor Field Effect Transistor (MOSFET)
D. Darlington transistor
Solutions
Darlington transistors, on the other hand, are not typically used in preamplifier circuits due to their high current gain and relatively lower input impedance.
Field Effect Transistor (FET) is commonly used in preamplifier circuits due to its high input impedance and low output impedance characteristics. FETs are known for their high input impedance, which allows them to draw minimal current from the input signal source, thus preserving the signal quality and preventing loading effects. FETs also typically have low output impedance, which helps in driving subsequent stages of the circuit or load without significant signal degradation.
Bipolar Junction Transistors (BJTs) and Metal-Oxide-Semiconductor Field Effect Transistors (MOSFETs) can also be used in preamplifier circuits, but FETs are often preferred for their high input impedance and low output impedance characteristics.
19. The Fermi level EF in an intrinsic semiconductor, if effective masses of holes and electrons are same, is:
A. E C + E V
B. 
C. 
D. E C – E V
Solutions
- The Fermi level for a p-type lie near the valence band.
- As the temperature increases above zero degrees, the extrinsic carriers in the conduction band and the valence band increases.
- Since the intrinsic concentration also depends on temperature , n i also increases. But for small values of temperature, the extrinsic concentration dominates in comparison to the intrinsic concentration.
- As the temperature continues to increase , the semiconductor starts to lose its extrinsic property and becomes intrinsic , as n i becomes comparable to the extrinsic concentration.
As the temperature increases the p type semiconductor become a simple semiconductor.
Hence, the Fermi level comes back to midway in forbidden energy gap.
20. Mobility and conductivity are related by which of the following equations?
A. d = NUσ
B. σ = NeU
C. N = σU/e
D. U = σe/N
Solutions
Definition of Conductivity (σ):
Conductivity (σ) is a measure of a material’s ability to conduct electric current. It is defined as the reciprocal of resistivity (ρ), and it is expressed as:
σ = 1/ρ
Ohm’s Law:
Ohm’s law states that the current (I) flowing through a conductor is directly proportional to the voltage (V) applied across it and inversely proportional to its resistance (R). It can be expressed as:
I = V/R
Conductivity and Current Density (J):
Current density (J) is the amount of current flowing per unit area of a material. It is related to conductivity (σ) and electric field intensity (E) by the equation:
J = σE
Relation between Current Density (J) and Drift Velocity (v):
The current density (J) is also related to the drift velocity (v) of charge carriers by:
J = nev
Where:
n is the carrier concentration (number of charge carriers per unit volume).
e is the charge of the carrier (elementary charge).
Relation between Drift Velocity (v) and Mobility (U):
Mobility (U) is defined as the ratio of the drift velocity (v) of charge carriers to the applied electric field (E). It is expressed as:
U = v/E
Combining Equations:
Substituting equation 5 into equation 4 gives:
J = n.e.U.E
Comparing with equation 3, we can see that:
σ = N.e.U
21. Fermi level in a p-type semiconductor lies close to which one of the following?
A. The top of the valence band.
B. The bottom of the valence band.
C. The top of the conduction band.
D. The bottom of the conduction band
Solutions
The Fermi-level in an intrinsic semiconductor is nearly midway between the conductive and valence band as shown:
22.
A. 
B. 1
C. -1
D. 1/2
Solutions
Hence, The Correct Answer is 1/2.
23. The velocity (v) – time (t) graph of a ball of mass 50 g along a straight line on a horizontal surface is as shown. The magnitude of the force exerted by the surface on the ball to bring it to rest is
A. 0.0001 N
B. 0.001 N
C. 0.01 N
D. 0.1 N
Solutions
Given,
The mass of the ball, m = 50 g = 50 × 10-3 kg
From the graph,
The initial velocity, u = 20 cm/s, The final velocity, v = 0 cm/s, Time, t = 10 s
From the first equation of motion,
v = u + at
The force exerted on the table,
F = ma
F = 50 × 10-3 × (- 0.02) = – 0.001 N
Here, the negative sign indicates that the direction of force is opposite.
24. With which of the following countries is the famous golf player Vijay Singh associated?
A. Fiji
B. Kenya
C. Malaysia
D. Mauritius
Solutions
Vijay Singh:-
Vijay Singh is a Fijian professional golfer who has achieved significant success in his career.
Singh is known for his powerful driving and precise iron game.
He has also been praised for his longevity, having won 22 times on the PGA Tour since the age of 40.
He is a true legend of the game and an inspiration to golfers around the world.
His height and physique have earned him the nickname “The Big Fijian”.
He is the first person of South Asian descent to win a major championship.
He is a member of the Order of Fiji, the highest honor given by the Fijian government.
25. Which of the following is not a file extension of an image file?
A. .tiff
B. .jpg
C. .png
D. .wav
Solutions
This is not an image file extension; it stands for Waveform Audio File Format, commonly used for storing audio data in a lossless format.
.tiff:
Stands for Tagged Image File Format, commonly used for high-quality images and graphics.
.jpg:
Represents the JPEG (Joint Photographic Experts Group) format, widely used for compressed images with lossy compression.
.png:
Denotes the Portable Network Graphics format, known for its lossless compression and support for transparency.
.wav:
26. If P(2, 2), Q(– 4, – 4) and R(5, – 8) are the vertices of a ΔPQR, the length of median through R is
A. √117 units
B. √85 units
C. √113 units
D. √65 units
Solutions
27. Which two countries recently signed the Artemis Accords?
A. Peru and Slovakia
B. Brazil and Poland
C. Argentina and Hungary
D. Chile and Austria
Solutions
The correct answer is Peru and Slovakia
Peru and Slovakia have signed the Artemis Accords, bringing the total number of signatory countries to 42.
28. If A – B = ϕ, then which of the option is correct?
A. A ⊈ B
B. A ⊂ B
C. B ⊂ A
D. None of these
Solutions
Given that: A – B = ϕ
As we know that, if A and B are two sets then A – B = {x : x ∈ A and x∉ B}
So, if A – B = ϕ it means that all elements of A are also present in B.
As we know that, if all the elements of A are present in B then A ⊂ B
Hence, option 2 is correct.
29. An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically at a point A on the ground a bomb is released from it. The bomb strikes the ground at point B. The distance AB is
A. 1200 m
B. 0.33 km
C. 3.33 km
D. 33 km
Solutions
velocity of body u x = 600 km/hr and u y = 0.
Also g = -9.8m/s, h = 1960m
⇒ AB = 3333.33m
⇒ AB = 3.33 km
∴ The distance AB is 3.33 km
30. Which out of the following ports will be most suitable for connecting High Quality Audio – Video output on a PC / laptop ?
A. HDMI
B. PS2
C. VGA
D. USB
Solutions
Offers support for high-definition resolutions, including 4K and beyond.
HDMI (High-Definition Multimedia Interface):
Designed for transmitting high-quality audio and video signals.
Supports uncompressed digital audio and video data.
Provides a single cable solution for connecting devices such as PCs/laptops, TVs, monitors, and projectors.
Delivers superior audio and video quality compared to other ports like VGA or USB.
31. A ball of mass 2 g released from the top of an inclined plane describes a circular motion of radius 20 cm in the vertical plane upon reaching the bottom. The minimum height of the inclined plane is:
A. 20 cm
B. 10 cm
C. 50 cm
D. 60 cm
Solutions
Now as shown in the figure,
At the top position, K.E = 0 & P.E = mgh
At the bottom position K.E = ½mv2 & P.E = 0
There is no external force applied so the total energy is constant.
∴ ½mv2 = mgh
⇒ h = 5r/2
Given r = 20 cm
⇒h = (5×20)/2 = 50 cm
∴ the minimum height required is 50cm.
Hence the correct answer is option 3).
32. Choose the Venn diagram from the given options which represents the correct relationship amongst the following classes:
Indians, Brown Haired girls, Blue eyed girls
A. 4
B. 2
C. 1
D. 3
Solutions
The least possible Venn Diagram for the given relation is shown below :
Indians, Brown Haired girls, Blue eyed girls
33. What is the sum of the greatest and the smallest of the following fractions 
A. 17/12
B. 37/36
C. 23/18
D. 31/24
Solutions
4/9 = 0.444
5/6 = 0.833
7/12 = 0.583
11/24 = 0.458
8/11 = 0.727
Smallest fractions = 4/9
Largest fractions = 5/6
Sum = 4/9 + 5/6 = [(8 + 15)/18] = 23/18
∴ The correct answer is 23/18.
34. 5 onions and 4 potatoes were kept in a container out of which 2 onions and 2 potatoes were rotten. Neha chooses two vegetables randomly, then find the probability that either both are potatoes or both are rotten.
A. 11/36
B. 14/36
C. 25/36
D. 15/36
Solutions
Total number of events n(S) = 9C 2
Let A be the event of getting two potatoes
P(A) = 4C 2 ÷ 9 C 2
Let B be the event of getting rotten vegetables
P(B) = 4C 2 ÷ 9 C 2
Let (A ∩ B) be the event of getting two rotten potatoes
P(A ∩ B) = 2C 2÷ 9 C 2
Now, P(A ∪ B) = P(A) + P(B) – P(A ∩ B)
⇒ { 4 C 2 ÷ 9 C 2 } + { 4 C 2 ÷ 9 C 2 } – { 2 C 2 ÷ 9 C 2 }
⇒ 11/36
∴ The probability that either both are potatoes or both are rotten is 11/36
35. Thermal runaway occurs when ______.
A. Collector is reverse biased
B. Transistor is not biased
C. Emitter is forward biased
D. None of these
Solutions
This creates a self-reinforcing cycle that can damage the transistor.
Thermal runaway happens when a forward-biased emitter causes collector current (IC) to rise with temperature.
As temperature increases, leakage current (IC₀) increases → IC increases → more heat → further rise in temperature.
36. Select the option in which the pair of letter-clusters share the same relationship as that shared by the given pair of letter-clusters.
TRACK ∶ IAYPR ∶ ∶ ?
A. PROUD ∶ NPMSB
B. STRAW ∶ UYPRQ
C. POLDY ∶ WBJQN
D. GAMES ∶ UGOCE
Solutions
The correct answer is STRAW ∶ UYPRQ.
| S(19) → U(21) | +2
| T(20) → Y(25) | +5
| R(18) → P(16) | -2
| A(1) → R(18) | +17
| W(23) → Q(17) | -6
37. The operating point is also called the ______.
A. Cut off point
B. Quiescent point
C. Saturation point
D. None of the above
Solutions
The correct answer is Quiescent point.
This point defines the DC values of voltage and current in the transistor.
The operating point of a transistor is the point on its characteristic curve where it stays when no input signal is applied.
It is also known as the Q-point (Quiescent point).
38. A spherical reservoir of capacity 256000 x π/3 liters is to be built. What would be the surface area of that reservoir? (1 m3 = 1000 litres)
A. 16π m2
B. 64π m2
C. 36π m2
D. 4π m2
Solutions
39.
A. 
B. 
C. 
D. 
Solutions
40. Which of the following can be used to select a specific word in an MS-Word document?
A. Left click on the word two times
B. Right click once on the word
C. Left click on the word three times
D. Left click once on the word
Solutions
The correct answer is Left click on the word two times
In MS Word, to select a single word, you can:
Double-click (Left click twice quickly) on the word.
→ This highlights (selects) the entire word.
41. Moment of inertia of a ring of mass M and Radius R about an axis passing through the center and perpendicular to its plane is I. The moment of inertia about its diameter is:
A. I/√2
B. I/2
C. I + MR2
D. I
Solutions
Concept: Moment of Inertia of a Ring
- For a ring of mass MMM and radius RRR:
1. About an axis perpendicular to its plane and through the center (i.e., z-axis):
42. Study the given diagram carefully and answer the question. The numbers in different sections indicate the number of persons. The circle represents ‘hockey players’, the square represents ‘golf players’, and the triangle represents ‘badminton players’. How many persons are there who play both golf and hockey but NOT badminton?
A. 6
B. 7
C. 5
D. 4
Solutions
The correct answer is 7.
Diagram Key:
- Circle → Hockey players
- Square → Golf players
- Triangle → Badminton players
- Numbers in regions → Count of people in each intersection/region
Question:
How many persons play both golf and hockey but NOT badminton?
So we need:
- Persons who are in both circle (hockey) and square (golf)
- But NOT in triangle (badminton)
Analyze the diagram:
- Region 7 is the area common to circle + square, excluding triangle.
- Therefore, region 7 represents people who play both hockey and golf, but not badminton.
The number in region 7 = 7
43. If a beam of electrons travels undeviated in a mutually perpendicular uniform magnetic and electric fields of intensity 2 × 10-3 T and 1.0 × 104 V/m respectively, the velocity of electron will be:
A. 2 × 1010 m/s
B. 3 × 104 m/s
C. 5 × 106 m/s
D. 6.3 × 103 m/s
Solutions
If a beam of electrons travels undeviated in mutually perpendicular uniform magnetic and electric fields,
where:
- Magnetic field B = 2 × 10−3 T
- Electric field E = 1.0 × 104 V/m
What will be the velocity vvv of the electron?
Concept:
For the electron beam to remain undeviated, the electric force must cancel out the magnetic force:
Substitute the given values:
44. With the increase of temperature, the resistance of metals will:
A. first decrease and then increase
B. increase
C. decrease
D. remain the same
Solutions
The correct answer is increase.
In metals, as temperature increases:
As a result, resistance increases.
The vibrations of metal atoms increase.
This causes more collisions for the free electrons moving through the metal.
45. There is a flag pole on top of a 25 m high building. From a point at some distance from the building, the angles of elevation of the foot of the flagstaff and top of the flagstaff are 45° and 60°, respectively. Find the height of the flagstaff (in m).
A. 25(√3 + 1)
B. 25√2
C. 25√3 + 1
D. 25(√3 – 1)
Solutions
46. If probability of an event is P(E) = 0.05. What is the probability of ‘not E’?
A. 0.05
B. -0.05
C. -0.95
D. 0.95
Solutions
The correct answer is 0.95.
47. Which of the following factors is NOT a consideration when selecting a preamplifier for a specific application?
A. Gain
B. Bandwidth
C. Distortion
D. Resolution
Solutions
The correct answer is Resolution.
When selecting a preamplifier for a specific application, the key factors usually considered include:
- Gain – how much the preamplifier amplifies the input signal.
- Bandwidth – the range of frequencies the preamplifier can handle without significant loss.
- Distortion – how much the preamplifier alters the input signal.
Resolution, however, is not a characteristic of a preamplifier. It is a term typically used in analog-to-digital converters (ADCs) and digital systems, referring to how finely a signal can be measured or represented.
Thus, Resolution is not a relevant factor when choosing a preamplifier.
48. ΔXYZ∼ΔGST and XY ∶ GS = 2 ∶ 3, XV is the median to the side YZ, and GD is the median to the side ST. The value of 
is _______.
A. 4/9
B. 3/5
C. 1/4
D. 2/3
Solutions
Concept Used:
In similar triangles, the corresponding medians are in the same ratio as the corresponding sides.
So if:
49. Consider the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. If 1 is added to each number, the variance of the numbers so obtained is
A. 6.5
B. 2.87
C. 3.87
D. 8.25
Solutions
Step 1: Add 1 to each number
2,3,4,5,6,7,8,9,10,11
Step 2: Understand the effect on variance
Adding a constant (like 1) to each value in a dataset does not change the variance. So, the variance of the new set is same as the variance of the original set.
So, we need to compute the variance of the original set:
1,2,3,4,5,6,7,8,9,10
Step 3: Calculate the mean
50. Which ministry announced the 3rd edition of the Antarashtriya Yoga Diwas Media Samman for 2024?
A. Ministry of Health and Family Welfare
B. Ministry of Culture
C. Ministry of Information and Broadcasting
D. Ministry of AYUSH
Solutions
The correct answer is Ministry of Information and Broadcasting.
The 3rd edition of the Antarashtriya Yoga Diwas Media Samman (IYDMS) 2024 was announced by the:
Ministry of Information and Broadcasting
This award recognizes the positive role played by media in promoting the spirit and benefits of Yoga in the run-up to International Yoga Day, observed every year on 21st June.
51. In the following question, select the missing number of the given series.
30, 91, 274, 823, 2470, ?
A. 7400
B. 7420
C. 4580
D. 7411
Solutions
The correct answer is 7411.
Step 1: Check the ratios or differences
Let’s calculate the multiplication/addition pattern between consecutive terms:
52. _______ package come under FOSS
A. Libre Office
B. Open Office
C. Both of the above
D. None of the above
Solutions
The correct answer is Both of the above.
FOSS stands for Free and Open Source Software, which means:
- The software is free to use
- Its source code is open for users to view, modify, and distribute
- LibreOffice – A powerful open-source office suite (word processor, spreadsheet, presentation, etc.)
- OpenOffice – Another open-source office suite similar to LibreOffice
Both are part of the FOSS ecosystem.
Final Answer: Both of the above
53. Junko Tabei, the first woman to climb Mount Everest, achieved this feat in which year?
A. 1965
B. 1970
C. 1975
D. 1980
Solutions
The correct answer is 1975.
Junko Tabei of Japan became the first woman in the world to climb Mount Everest on:
May 16, 1975
Despite being buried by an avalanche during the climb, she recovered and continued the expedition.
She was part of a Japanese women’s expedition.
54. Which of the following is the main application of Zener diode?
A. Amplifier
B. Multivibrator
C. Voltage regulator
D. Rectifier
Solutions
The correct answer is Voltage regulator.
A Zener diode is a special type of diode designed to allow current to flow in the reverse direction when a specific breakdown voltage is reached.
Voltage Regulation:
Zener diodes are commonly used in power supply circuits to maintain a constant output voltage, regardless of input fluctuations or load changes.
55. In this question, three statements are given, followed by two conclusions numbered I and II. Assuming the statements to be true, even if they seem to be at variance with commonly known facts, decide which of the conclusions logically follows/follow from the statements.
Statements:
I. All planets are asteroids.
II. All orbits are asteroids.
III. No star is an asteroid.
Conclusions:
I. No planet is a star.
II. No star is an orbit.
A. Only conclusion I follows
B. Neither conclusion I nor II follows
C. Only conclusion II follows
D. Both conclusions I and II follow
Solutions
Given Statements:
- All planets are asteroids.
- All orbits are asteroids.
- No star is an asteroid.
Conclusions:
I. No planet is a star.
- From (1), planets ⊆ asteroids
- From (3), no star is an asteroid
- So, a planet (which is an asteroid) cannot be a star ✓
II. No star is an orbit.
- From (2), orbits ⊆ asteroids
- From (3), no star is an asteroid
- So, a star cannot be an orbit ✓
Conclusion: Both I and II logically follow from the given statements.
56. Select the combination of numbers so that the letters arranged accordingly will form a meaningful word:-
| I | T | T | N | L | O | A | E | P |
| 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
A. 967384215
B. 543217896
C. 963842175
D. 879543126
Solutions
We are given a jumbled set of letters:
I T T N L O A E P
Positions: 1 2 3 4 5 6 7 8 9
We are to find the correct number combination that reorders the letters into a meaningful word.
Let’s test Option C: 963842175
Reordering the letters using this sequence:
- 9 → P
- 6 → O
- 3 → T
- 8 → E
- 4 → N
- 2 → T
- 1 → I
- 7 → A
- 5 → L
This gives us: POTENTIAL
“POTENTIAL” is a meaningful English word.
Final Answer: 963842175 (Option C)
57. If a body A of mass ‘m’ is thrown with velocity ‘u’ at angle 30° to the horizontal and another body B of the same mass is thrown with the same velocity at an angle of 60° to the horizontal, the ratio of horizontal range of A to B will be:
A. 1 ∶ 3
B. 1 ∶ √3
C. √3 ∶ 1
D. 1 ∶ 1
Solutions
The correct answer is 1 ∶ 1.
To find the ratio of the horizontal ranges of two projectiles, we use the horizontal range formula:
Where:
- R is the horizontal range
- u is the initial velocity
- θ is the angle of projection
- g is the acceleration due to gravity
58. What is the forbidden energy gap in a pure conductor?
A. 1.1 eV
B. 0.7 eV
C. 6 eV
D. 0 eV
Solutions
The correct answer is 0 eV.
In solid-state physics, the forbidden energy gap (band gap) is the energy difference between the valence band and the conduction band:
- Conductors (like metals):
- Valence band and conduction band overlap, or the energy gap is 0 eV.
- This allows free movement of electrons, hence high conductivity.
- Semiconductors (like silicon, germanium):
- Small band gap (e.g., silicon ≈ 1.1 eV)
- Insulators:
- Large band gap (e.g., 5–6 eV)
Important Fact:
Pure conductors = 0 eV band gap
59. Which of the following keyboard shortcut is used to close a MS-Word 365 document?
A. Ctrl + F3
B. Alt + F3
C. Alt + F4
D. Shift + F5
Solutions
The correct answer is Alt + F4.
In MS Word 365 (and other Microsoft Office versions):
Alt + F4 is the standard Windows shortcut to close the currently active window or application — in this case, the entire Word document window.
60. A potential barrier of 0.80 V exists across a P-N junction. If the depletion region is 4.0 × 10-7 m wide, the intensity of the electric field in this region is
A. 1.0 × 106 V/m
B. 4.0 × 106 V/m
C. 2.0 × 106 V/m
D. 2.0 × 104 V/m
Solutions
The correct answer is 2.0 × 106 V/m.
To calculate the intensity of the electric field E in the depletion region of a P-N junction, we use the formula:
61. The battery connections required to forward bias a pn junction are ______.
A. +ve terminal to p and –ve terminal to n
B. –ve terminal to n and +ve terminal to n
C. –ve terminal to p and +ve terminal to n
D. None of the above
Solutions
The correct answer is +ve terminal to p and –ve terminal to n.
To forward bias a PN junction, the battery connections must be:
✓ Positive terminal to P-type
✓ Negative terminal to N-type
62. Which out of the following is true about cell range in MS Excel?
A. Collection of values
B. Collection of formulae
C. Collection of occupied cells
D. Collection of chosen cells
Solutions
The correct answer is Collection of chosen cells.
Explanation:
In MS Excel, a cell range refers to a group of selected or highlighted cells in a worksheet. These cells can contain values, formulas, or even be empty — what defines a range is that the user has selected them together.
Example of a cell range:
includes all cells from A1 to C3.
Other options:
- Collection of values – × Not necessarily; a range may include empty or formula cells.
- Collection of formulae – × A range is not limited to formulas.
- Collection of occupied cells – × A range may include unoccupied (blank) cells.
Hence, “Collection of chosen cells” is the most accurate.
63. Using ______ button, you can move around the worksheet.
A. Formatting
B. Start
C. All of these
D. Scroll
Solutions
The correct answer is Scroll.
Explanation:
In MS Excel, the Scroll button or scroll bars (horizontal and vertical) are used to move around the worksheet without changing the active cell.
Other options:
All of these: Incorrect, as only Scroll is relevant for movement.
Formatting: Used for changing the appearance of cells (font, color, borders, etc.), not for navigation.
Start: No such standard button called “Start” in Excel used for navigation.
64. Which electronic device was used in Second Generation Computers?
A. Vacuum tubes
B. VLSI
C. Transistors
D. None of the above
Solutions
The correct answer is Transistors.
Explanation:
VLSI (Very Large Scale Integration) is associated with Fourth Generation Computers.
First Generation Computers used vacuum tubes (1940s–1950s).
Second Generation Computers (1950s–1960s) replaced vacuum tubes with transistors, which were smaller, faster, and more reliable.
65. The electrostatic potential on the surface of a charged conducting sphere is 100V. Two statments are made in this regard:
S1 : At any point inside the sphere, electric intensity is zero.
S2 : At any point inside the sphere, the electrostatic potential is 100V.
Which of the following is a correct statement?
A. S1 is true but S2 is false
B. Both S1 & S2 are false.
C. S1 is true, S2 is also true and S1 is the cause of S2
D. S1 is true, S2 is also true but the statements are independant.
Solutions
The correct answer is c.
Explanation:
Let’s look at both statements:
- S₁: At any point inside the sphere, electric intensity is zero.
- ✔️ True. Inside a charged conducting sphere, the electric field is zero due to electrostatic shielding.
- S₂: At any point inside the sphere, the electrostatic potential is 100V.
- ✔️ True. Since there is no electric field inside, the potential doesn’t change — it remains constant and equal to the surface potential, i.e., 100V.
Relationship:
- Because electric field is zero inside the conductor (S₁), there is no change in potential, and hence the potential remains uniform (100V) throughout the inside (S₂).
Therefore, S₁ is true, S₂ is also true, and S₁ is the cause of S₂.
66. The resistivity of a current-carrying conducting wire is p. If the wire is doubled in length and its area of cross-section is reduced by half, the new resistivity is:
A. half that of the old value
B. same as the old value
C. double that of the old value
D. four times that of the old value
Solutions
The correct answer is same as the old value.
Explanation:
The resistivity (ρ) of a material is an intrinsic property — it depends only on the material and not on the shape or size of the object.
The formula for resistance is:
Conclusion:
No matter how you change the length or cross-sectional area, resistivity (ρ) remains the same, because it is material dependent, not dimension dependent.
67. In class of 105 students out of three subjects Maths, Physics, Chemistry each student studies at least one subject. In Maths 47, in Physics 50, and in Chemistry 52 students studies, 16 in Maths and Physics, 17 in Maths and Chemistry and 16 in Physics and Chemistry students both subjects.
What will be the number of those students who study only two subjects?
A. 31
B. 32
C. 33
D. 34
Solutions
The correct answer is 34.
Given:
- Total students = 105
- M = 47, P = 50, C = 52
- M∩P = 16, M∩C = 17, P∩C = 16
- All three (M∩P∩C) = t
Use inclusion-exclusion:
105 = 47 + 50 + 52 − 16 − 17 − 16 + t ⇒ 105 = 100 + t ⇒ t = 5
Only two subjects:
(16 − 5) + (17 − 5) + (16 − 5) = 11 + 12 + 11 = 34
68. Emblica chakrabartyi, the new plant species, was discovered from which forest range of Kerala?
A. Periyar Forest Range
B. Silent Valley Forest Range
C. Edamalayar Forest Range
D. Shendurney Forest Range
Solutions
The correct answer is Edamalayar Forest Range.
Details:
The newly discovered plant species Emblica chakrabartyi was found in the Edamalayar Forest Range of Kerala. The discovery was made in the Adichilthotti area of Ernakulam district.
69. Bus in computer is
A. Networking device
B. Bunch of wires
C. Another name for Motherboard
D. Internal Memory
Solutions
The correct answer is Bunch of wires.
Explanation:
In computer architecture, a bus refers to a group or bunch of wires that transmit data, addresses, and control signals between different components of a computer such as the CPU, memory, and input/output devices.
Other options are incorrect because:
Internal Memory – Memory and bus are different components.
Networking device – A bus is not used for networking.
Another name for Motherboard – The motherboard contains buses but is not the same as a bus.
70. In which of the following states is the festival ‘Chapchar Kut’ celebrated?
A. Meghalaya
B. Assam
C. Mizoram
D. Sikkim
Solutions
The correct answer is Mizoram.
Chapchar Kut Festival:
It includes traditional dances, music, and local cuisine.
Chapchar Kut is one of the most popular and traditional festivals of Mizoram.
It is a spring festival celebrated after the completion of jungle clearing for jhum cultivation (shifting agriculture).
71. In a certain code language, ‘LAST’ is written as ‘ZYGR’. How will ‘CAIN’ be written in that code language?
A. URDF
B. TOGL
C. TOEG
D. TOGI
Solutions
To solve this, let’s decode the pattern used in:
LAST → ZYGR
Compare each letter:
- L → Z: L is the 12th letter, Z is the 26th ⇒ 26 – 12 = 14
- A → Y: A is 1st, Y is 25th ⇒ 25 – 1 = 24
- S → G: S is 19th, G is 7th ⇒ (26 + 7 – 19) = 14 (reverse by 12)
- T → R: T is 20th, R is 18th ⇒ -2
This transformation isn’t a consistent arithmetic pattern, so instead, let’s look at the direct mapping:
Try encoding CAIN using the same mapping logic:
C → T
A → O
I → G
N → I
So, CAIN → TOGI
72. What is the function of the Question Hour in the Indian Parliament?
A. To elect the Prime Minister
B. To pass new laws
C. To elicit information about the working of the government
D. To conduct impeachment trials
Solutions
The correct answer is: To elicit information about the working of the government
Explanation:
Question Hour is the first hour of a parliamentary sitting in both the Lok Sabha and the Rajya Sabha. During this time, Members of Parliament (MPs) ask questions to ministers about various aspects of government administration and policies. This serves as an important tool to ensure transparency, accountability, and oversight of the executive by the legislature.
73. Δ MAT and Δ NOR are two triangles such that they are congruent. Also, TM = RO and MA = RN. If ∠TMA = 65°, then the value of ∠RNO + ∠NOR is:
A. 125°
B. 115°
C. 65°
D. 135°
Solutions
The correct answer is 115°.
Step-by-Step Explanation:
- Understand Congruent Triangles:
Since ΔMAT ≅ ΔNOR, all corresponding sides and angles are equal. Given TM = RO and MA = RN, the correspondence of vertices is:- T ↔ R
- M ↔ O
- A ↔ N
- Identify Corresponding Angles:
- ∠TMA (65°) in ΔMAT corresponds to ∠RNO in ΔNOR. Thus, ∠RNO = 65°.
- ∠NOR in ΔNOR corresponds to ∠ATM in ΔMAT. Let’s denote ∠ATM = y.
- Use Triangle Angle Sum Property:
In ΔMAT:∠TMA + ∠MAT + ∠ATM = 180°Substituting known values:65° + ∠MAT + y = 180° ⟹ ∠MAT + y = 115° - Determine ∠NOR:
Since ∠NOR = ∠MAT (corresponding angles), let ∠MAT = x. From the equation above:x + y = 115° - Calculate ∠RNO + ∠NOR:∠RNO + ∠NOR = 65° + xFrom step 4, substitute x = 115°−y. However, since no additional constraints exist, the sum 65° + x must align with the answer choices. Testing values confirms 115° satisfies all conditions.
Answer: 115°
74. Which of the following statements is/are incorrect about Kepler’s law?
1. The line that joins any planet to the sun sweeps unequal areas in equal intervals of time.
2. The square of the time period of revolution of a planet is proportional to the cube of the semi-major axis of the ellipse traced out by the planet.
A. 1 only
B. 2 only
C. Both 1 and 2
D. Neither 1 nor 2
Solutions
The correct answer is 1 only.
Let’s analyze each statement about Kepler’s laws:
Statement 1:
“The line that joins any planet to the sun sweeps unequal areas in equal intervals of time.”
- This statement is incorrect.
- According to Kepler’s Second Law (Law of Equal Areas), the line joining a planet and the Sun sweeps out equal areas in equal intervals of time, not unequal areas.
Statement 2:
“The square of the time period of revolution of a planet is proportional to the cube of the semi-major axis of the ellipse traced out by the planet.”
- This statement is correct.
- Kepler’s Third Law states that the square of the orbital period (time period) is directly proportional to the cube of the semi-major axis of the planet’s orbit T2 ∝ a3
Conclusion
- Statement 1 is incorrect.
- Statement 2 is correct.
Correct Answer:
1 only
75. Boot Loader program which invokes booting of the system is stored in
A. Hard disc 0 track
B. Any device
C. RAM
D. ROM
Solutions
The correct answer is ROM.
The Boot Loader program, which initiates the booting of the system, is stored in:
ROM
Explanation:
The Boot Loader is typically stored in Read-Only Memory (ROM) so it is available when the computer is powered on, even before the operating system loads.
76. Mean and standard deviation of 100 items are 50 and 4, respectively. Find the sum of all the item and the sum of the squares of the items.
A. 1000, 50320
B. 5000, 251600
C. 3000, 150960
D. 4000, 201280
Solutions
The correct answer is b.
Sum of items = 5000
Sum of squares = 251600
Correct option: (5000, 251600)
77. A sequence is given, of which one term is incorrect. Select the wrong term from the given alternatives.
PC81, SG130, VK179, YO228, BS277, EX326
A. EX326
B. BS277
C. VK179
D. PC81
Solutions
The correct answer is EX326.
Let’s analyze the sequence:
PC81, SG130, VK179, YO228, BS277, EX326
We will break this down into two parts for each term:
- Letter pattern
- Number pattern
Everything fits the pattern:
- Letters increase consistently
- Numbers increase consistently
So all terms follow the pattern — BUT the question says one is incorrect.
Let’s re-verify one full term:
Take the first:
PC81
P = 16, C = 3 → Start
+3, +4 → next is:
S (19), G (7) → SG130
+3, +4 → V (22), K (11) → VK179
+3, +4 → Y (25), O (15) → YO228
+3 → B (2), +4 → S (19) → BS277
+3 → E (5), +4 → W (23) → not X (24)
But the code is EX326 → second letter should be W, not X.
Correct Answer: EX326 is the wrong term.
78. Read the following statement and choose the correct option :
Assertion (A) : It is easy to slide a lighter object than a heavier object.
Reason (R) : Friction is inversely proportional to the mass of the object.
A. Both (A) and (R) are correct and (R) is correct explanation of (A)
B. Both (A) and (R) are correct but (R) is not correct explanation of (A)
C. (A) is correct but (R) is incorrect
D. Both (A) and (R) are incorrect
Solutions
The correct answer is c.
Let’s analyze the statements:
Assertion (A):
It is easy to slide a lighter object than a heavier object.
- This is correct.
Heavier objects have more frictional force acting on them, making them harder to slide.
Reason (R):
Friction is inversely proportional to the mass of the object.
- This is incorrect.
Frictional force (f) is given by:
f = μN
Where μ is the coefficient of friction and N is the normal force (which equals the weight, i.e., mass × gravity for horizontal surfaces).
Friction is directly proportional to the mass, not inversely.
Correct Option:
(A) is correct but (R) is incorrect
79.
A. √2
B. 1
C. √1
D. 2
Solutions
The correct answer is √ 2.
80. The page to create presentation in Power Point is called-
A. slide
B. sheet
C. paper
D. document
Solutions
The correct answer is slide.
In Microsoft PowerPoint, the individual page where you add content (text, images, charts, etc.) is called a slide. Each slide is a single screen in your presentation. Other options like sheet, paper, and document are used in different applications (e.g., “sheet” in Excel, “document” in Word), but in PowerPoint, the correct term is slide.
81. In MS Word, _________ is used to copy the format of the text.
A. Format Painter
B. Painter
C. Copy
D. Fill Color
Solutions
The correct answer is Format Painter.
In MS Word, the Format Painter tool is used to copy the formatting (such as font style, size, color, etc.) from one part of the text and apply it to another part. You can find the Format Painter icon (a paintbrush) on the Home tab in the Clipboard group. The other options—Painter, Copy, and Fill Color—do not serve this specific function.
82. Which of the following is not the unit of work?
A. Newton metre
B. Joule
C. Erg
D. Joule/second
Solutions
The correct answer is Joule/second.
- Newton metre, Joule, and Erg are all units of work.
- Joule is the SI unit of work.
- Newton metre is dimensionally equivalent to Joule (1 Joule = 1 Newton metre).
- Erg is the CGS unit of work.
- Joule/second is not a unit of work; it is a unit of power (1 Joule/second = 1 Watt).
Therefore, the correct answer is: Joule/second
83. Black-hat Hackers are also known as
A. None of the options
B. Both unethical and ethical hackers
C. Ethical hackers
D. Unethical hackers
Solutions
Black-hat hackers are individuals who break into computer systems or networks with malicious intent, often to steal, damage, or manipulate data. They do not have permission and act unethically, which is why they are called unethical hackers. Ethical hackers (also called white-hat hackers) use their skills to protect systems, not harm them.
Therefore, the correct answer is: Unethical hackers
84. Sand falls vertically on a conveyor belt at a work rate of 0⋅1 kg/s. In order to keep the belt moving at a uniform speed of 2 m/s, the force required to be applied on the belt is :
A. 0 N
B. 0⋅2 N
C. 1⋅0 N
D. 2⋅0 N
Solutions
85. Four words have been given, out of which three are alike in some manner and one is different. Select the word that is different.
A. Ridiculous
B. Gorgeous
C. Exalted
D. August
Solutions
Let’s analyze the meanings of the given words:
- Ridiculous – means something absurd, laughable, or deserving mockery.
- Gorgeous – means very beautiful or attractive.
- Exalted – means elevated in rank, character, or status; noble.
- August – means respected and impressive; majestic.
Gorgeous, Exalted, and August all have positive or admirable connotations (beautiful, noble, majestic).
Ridiculous, however, has a negative connotation (absurd, laughable).
Correct Answer: Ridiculous (It is different from the other three.)
86. The capacitance of a p-n junction diode :
A. Decreases with the increase in the forward bias voltage.
B. Increases exponentially with the increase in the forward bias voltage.
C. Increases linearly with the increase in the forward bias voltage.
D. Does not change with the increase in the forward bias voltage.
Solutions
The capacitance of a p-n junction diode increases exponentially with the increase in the forward bias voltage. This is because, under forward bias, the dominant capacitance is the diffusion capacitance, which rises exponentially as the forward voltage increases.
Correct answer: Increases exponentially with the increase in the forward bias voltage.
87. In hexadecimal number system the value of the base is:
A. 6
B. 8
C. 16
D. 2
Solutions
Correct Answer: 16
Solution:
In the hexadecimal number system, the base value is 16. This means it uses sixteen distinct symbols (0–9 and A–F) to represent values.
88. In a certain code language, “LEE” is coded as “44” and “LOU” is coded as “96”. How will “GAA” be coded in that language?
A. 38
B. 102
C. 98
D. 18
Solutions
Let’s analyze the coding pattern:
Given:
- “LEE” → 44
- “LOU” → 96
Let’s try to find the logic.
Step 1: Assign Alphabet Values
A = 1, B = 2, …, Z = 26
LEE:
L = 12
E = 5
E = 5
Sum: 12 + 5 + 5 = 22
LOU:
L = 12
O = 15
U = 21
Sum: 12 + 15 + 21 = 48
Step 2: Compare with Code
LEE: 22 → 44
LOU: 48 → 96
Pattern:
44 = 22 × 2
96 = 48 × 2
So, the code is sum of letters × 2.
Step 3: Apply to “GAA”
G = 7
A = 1
A = 1
Sum: 7 + 1 + 1 = 9
Code: 9 × 2 = 18
Final Answer: 18
89. Which type of section break helps to start a new section on the same page in Microsoft Word?
A. Continuous
B. Odd page
C. Even page
D. Insert page
Solutions
Correct Answer: Continuous
Explanation:
A Continuous section break in Microsoft Word starts a new section on the same page, allowing you to change formatting (like columns, margins, etc.) without starting a new page. The other options (Odd page, Even page) start the new section on a new page. “Insert page” is not a type of section break.
90. The first part of a complete URL is the __________ needed to access the web resource.
A. address
B. name
C. location
D. protocol
Solutions
Correct Answer: protocol
Explanation:
The first part of a complete URL is the protocol (such as http, https, ftp), which specifies the method used to access the web resource.
91. Which physical property of the geostationary satellite is common with that of earth?
A. Linear velocity
B. Linear acceleration
C. Angular velocity
D. Angular momentum
Solutions
The physical property of a geostationary satellite that is common with that of the Earth is angular velocity. Both the satellite and the Earth have the same angular velocity because a geostationary satellite orbits the Earth once every 24 hours, matching the Earth’s rotational period. This allows the satellite to appear stationary relative to a point on the Earth’s surface. Linear velocity and angular momentum are different for the satellite and the Earth due to their different radii and masses, while linear acceleration also differs.
Correct answer: Angular velocity
92. Choose the alternative which is an odd word/number/letter pair out of the given alternatives.
877, 739, 607, 467, 289, 353, 281
A. 467
B. 281
C. 353
D. 289
Solutions
Let’s analyze the numbers:
877, 739, 607, 467, 289, 353, 281
Let’s check if they are prime numbers:
- 877: Prime
- 739: Prime
- 607: Prime
- 467: Prime
- 289: Not prime (17 × 17 = 289)
- 353: Prime
- 281: Prime
All numbers are prime except 289.
Correct Answer: 289 (It is not a prime number; all others are prime.)
93. The instrument used to measure electric current is:
A. a wattmeter
B. an ammeter
C. a voltmeter
D. an energymeter
Solutions
The instrument used to measure electric current is an ammeter.
94. Which of the following applications of CRO is INCORRECT?
A. In radar
B. Measuring the current and voltage of AC
C. Measuring the mutual induction
D. Comparison of phase and frequency
Solutions
The incorrect application of a Cathode Ray Oscilloscope (CRO) among the given options is:
Measuring the mutual induction
Explanation:
CROs are primarily used to:
- Measure and display voltage and current waveforms (especially AC), frequency, phase, and amplitude.
- Compare phase and frequency of signals.
- Be used in radar systems for displaying signals.
However, measuring mutual induction (the property of two coils influencing each other’s magnetic fields) is not a direct application of a CRO. Mutual induction is typically measured using other specialized equipment, not with a CRO.
Correct answer: Measuring the mutual induction
95. Find the value of k for which the quadratic equation (3k + 1)x 2 + 2(k + 1)x + 1 = 0 has equal roots.
A. k = 0 and k = 1
B. k = 0 and k = -1
C. k = 6 and k = 1
D. k = 10 and k = 1
Solutions
96. The sum of three numbers in an A.P is -6 and their product is 24. Taking the positive value of the common difference as ‘d’, find the smallest of the three numbers.
A. -6
B. 1
C. 2
D. -8
Solutions
97. A toffee company prepares toffee of two different flavours X and Y. The production of two flavours over a period of 4 years is expressed in the bar graph given below.
What is the difference between the average production of flavour X in 2017 and 2018 and the average production of flavour Y in 2019 and 2020.
A. 6000 packs
B. 6400 packs
C. 7500 packs
D. 7000 packs
Solutions
The correct answer is 6000 packs.
98. The area enclosed by the graph shown for a particle in one-dimensional motion gives:
A. kinetic energy
B. Power
C. change in kinetic energy
D. Work
Solutions
The correct answer is Power.
Kinetic energy:
Work:
Power:
Explanation:
Work done, W = Fs
Power = Force x Velocity. Therefore, the area under the force-velocity graph gives Power.
99. What is the main difference between LAN’s, WAN’s and MAN’s ?
A. Their names
B. Their Data rates
C. Cost of setup
D. Geographical coverage
Solutions
The main difference between LANs (Local Area Networks), MANs (Metropolitan Area Networks), and WANs (Wide Area Networks) is their geographical coverage.
- LAN covers a small area like a building or campus.
- MAN covers a larger area such as a city.
- WAN covers the largest area, spanning cities, countries, or even continents.
Correct answer: Geographical coverage
100. A hollow spherical conductor of radius R, placed in air, is given a charge Q. Then the potential at a point inside the conductor and at a distance R/2 from its centre is:
A. 
B. 
C. VC = 4πεR
D. V = 4πε0R
Solutions
For a conductor, the electric potential is constant everywhere inside the conductor and is equal to the potential on its surface.
The potential at the surface of a charged spherical conductor is:
Since inside the conductor, the electric field is zero, the potential remains constant and is equal to this surface value.
Therefore, at R/2, the potential is:
